I am trying to get input stream from something like this.
InputSource myInputSource = new InputSource(activity.getResources().openRawResource(com.MYCLass.R.xml.programs));
myXMLReader.parse(myInputSource);
and then call parse on the parser instance i Created. Some how i get nothing.
Works fine if I use a server XML....
Put the xml file into /res/raw folder. It looks like openRawResource opens resources from that folder only. You can also try getResources().getXml(com.MYCLass.R.xml.programs); which will return you an instance of XML parser.
A piece of code taken from @Krupa
InputStream object = this.getResources()
.openRawResource(R.raw.fileName);
Krupa
You can read the file by the following code :
InputStream object = this.getResources()
.openRawResource(R.rawFolderName.fileName);
来源:https://stackoverflow.com/questions/3464307/how-to-read-local-xml-file-is-resource-folder-as-a-input-stream-in-android