C : Modulus operator on unsigned int gives unexpected output

问题

#include <stdio.h>

main() {
    unsigned a = -20;
    unsigned b = 10;
    printf("%d\n", (a % b));
    printf("%d\n", (-20 % 10));
}

Output:
6
0

The second printf prints the expected value of 0 while the first printf prints 6. Why this unexpected output with unsigned ints?

回答1:

unsigned int can hold values from 0 to UINT_MAX, no negative values. So -20 is converted to -20 + UINT_MAX + 1.

On your system:

(-20 + UINT_MAX + 1) % 10 != -20 % 10

回答2:

And what are you expecting?

a % b is equivalent to, let's substitute the values and apply the unary - to the unsigned int value of 20, (UINT_MAX-20+1) % 10 and the type of the result is unsigned int and you're printing it with %d, which is wrong. You should use %u here.

来源：https://stackoverflow.com/questions/16122213/c-modulus-operator-on-unsigned-int-gives-unexpected-output