Create an instance of a class from a string

问题

Is there a way to create an instance of a class based on the fact I know the name of the class at runtime. Basically I would have the name of the class in a string.

回答1:

Take a look at the Activator.CreateInstance method.

回答2:

Its pretty simple. Assume that your classname is Car and the namespace is Vehicles, then pass the parameter as Vehicles.Car which returns object of type Car. Like this you can create any instance of any class dynamically.

public object GetInstance(string strFullyQualifiedName)
{         
     Type t = Type.GetType(strFullyQualifiedName); 
     return  Activator.CreateInstance(t);         
}

If your Fully Qualified Name(ie, Vehicles.Car in this case) is in another assembly, the Type.GetType will be null. In such cases, you have loop through all assemblies and find the Type. For that you can use the below code

public object GetInstance(string strFullyQualifiedName)
{
     Type type = Type.GetType(strFullyQualifiedName);
     if (type != null)
         return Activator.CreateInstance(type);
     foreach (var asm in AppDomain.CurrentDomain.GetAssemblies())
     {
         type = asm.GetType(strFullyQualifiedName);
         if (type != null)
             return Activator.CreateInstance(type);
     }
     return null;
 }

Now if you want to call a parameterized constructor do the following

Activator.CreateInstance(t,17); // Incase you are calling a constructor of int type

instead of

Activator.CreateInstance(t);

回答3:

I've used this method successfully:

System.Reflection.Assembly.GetExecutingAssembly().CreateInstance(string className)

You'll need to cast the returned object to your desired object type.

回答4:

Probably my question should have been more specific. I actually know a base class for the string so solved it by:

ReportClass report = (ReportClass)Activator.CreateInstance(Type.GetType(reportClass));

The Activator.CreateInstance class has various methods to achieve the same thing in different ways. I could have cast it to an object but the above is of the most use to my situation.

回答5:

I know I'm late to the game... but the solution you're looking for might be the combination of the above, and using an interface to define your objects publicly accessible aspects.

Then, if all of your classes that would be generated this way implement that interface, you can just cast as the interface type and work with the resulting object.

回答6:

For instance, if you store values of various types in a database field (stored as string) and have another field with the type name (i.e., String, bool, int, MyClass), then from that field data, you could, conceivably, create a class of any type using the above code, and populate it with the value from the first field. This of course depends on the type you are storing having a method to parse strings into the correct type. I've used this many times to store user preference settings in a database.

回答7:

To create an instance of a class from another project in the solution, you can get the assembly indicated by the name of any class (for example BaseEntity) and create a new instance:

  var newClass = System.Reflection.Assembly.GetAssembly(typeof(BaseEntity)).CreateInstance("MyProject.Entities.User");

回答8:

ReportClass report = (ReportClass)Activator.CreateInstance(Type.GetType(reportClass));

why do u want to write a code like this? If you have a class 'ReportClass' is available, you can instantiate it directly as shown below.

ReportClass report = new ReportClass();

The code ReportClass report = (ReportClass)Activator.CreateInstance(Type.GetType(reportClass)); is used when you dont have the necessary class available, but you want to instantiate and or or invoke a method dynamically.

I mean it is useful when u know the assembly but while writing the code you dont have the class ReportClass available.

来源：https://stackoverflow.com/questions/223952/create-an-instance-of-a-class-from-a-string

标签

.net

instantiation

system.type