How to get all children of a parent and then their children using recursion in query

我的未来我决定 提交于 2019-11-30 08:39:01
Aleksandr Fedorenko
DECLARE @Id int = your_UnitId
;WITH cte AS 
 (
  SELECT a.Id, a.parentId, a.name
  FROM customer a
  WHERE Id = @Id
  UNION ALL
  SELECT a.Id, a.parentid, a.Name
  FROM customer a JOIN cte c ON a.parentId = c.id
  )
  SELECT parentId, Id, name
  FROM cte

Demo on SQLFiddle

In case of parent id is a child of itself then we need to use a different query. For example, schema structure is like below

CREATE TABLE customer
(
  id int,
  parentid int,
  name nvarchar(10)
)

INSERT customer
VALUES(1,  1, 'aaa'),
  (2,  1,    'bbb'),
  (3,  2,    'ccc'),
  (4,  2,    'ddd'),
  (5,  1,    'eee'),
  (6,  5,    'fff'),
  (7,  5,    'ggg'),
  (8,  8,    'hhh'),
  (9,  8,    'iii'),
  (10, 8,    'jjj')

In this case, we need to use below query:

DECLARE @Id int = 1 -- your UnitId
;WITH cte AS 
 (
  SELECT a.Id, a.parentId, a.name
  FROM customer a
  WHERE parentid = @Id
  UNION ALL
  SELECT a.Id, a.parentid, a.Name
  FROM customer a JOIN cte c ON a.parentId = c.id
   and c.id != @Id

  )
  SELECT parentId, Id, name
  FROM cte
go
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