Is there a more direct and readable way to accomplish the following:
fn main() {
let a = [1, 2, 3];
let b = [4, 5, 6];
let c = [7, 8, 9];
let iter = a.iter()
.zip(b.iter())
.zip(c.iter())
.map(|((x, y), z)| (x, y, z));
}
That is, how can I build an iterator from n iterables which yields n-tuples?
You can use the izip!() macro from the crate itertools, which implements this for arbitrary many iterators:
use itertools::izip;
fn main() {
let a = [1, 2, 3];
let b = [4, 5, 6];
let c = [7, 8, 9];
// izip!() accepts iterators and/or values with IntoIterator.
for (x, y, z) in izip!(&a, &b, &c) {
}
}
You would have to add a dependency on itertools in Cargo.toml, use whatever version is the latest. Example:
[dependencies]
itertools = "0.8"
来源：https://stackoverflow.com/questions/29669287/how-can-i-zip-more-than-two-iterators