“Variable $foo will not stay shared” Warning/Error in Perl While Calling Subroutine

天大地大妈咪最大 提交于 2019-11-30 08:00:26

问题


Update3: If you like this posting please don't upvote me but upvote the genius answer by DVK below.

I have the following subroutines:

 use warnings;
#Input
 my @pairs = (
    "fred bill",
    "hello bye",
    "hello fred",
    "foo bar",
    "fred foo");

#calling the subroutine
my @ccomp = connected_component(@pairs);

use Data::Dumper;
print Dumper \@ccomp;

sub connected_component {

    my  @arr    = @_;
    my %links;

    foreach my $arrm (  @arr ) {
        my ($x,$y) = split(/\s+/,$arrm);;
        $links{$x}{$y} = $links{$y}{$x} = 1;

    }

    my %marked;  # nodes we have already visited
    my @stack;

    my @all_ccomp;

    for my $node (sort keys %links) {
        next if exists $marked{$node};
        @stack = ();
        connected($node);
        print "@stack\n";
        push @all_ccomp, [@stack];
    }

    sub connected {
        no warnings 'recursion';
        my $node = shift;
        return if exists $marked{$node};  # Line 43
        $marked{$node} = 1;
        push @stack, $node;   # Line 45
        my $children = $links{$node};  # Line 46
        connected($_) for keys %$children;
    }


    return @all_ccomp;
}

But why it gives this message:

Variable "%marked" will not stay shared at mycode.pl line 43.
Variable "@stack" will not stay shared at mycode.pl line 45.
Variable "%links" will not stay shared at mycode.pl line 46.

Is it harmful? Error? How can fix my code so that it get rid of that message?

Update1: I update the code that runs as is with the actuall error message

Update2: I tried to modify using sub as DVK suggested. And it WORKED!

use warnings;
#Input
 my @pairs = (
    "fred bill",
    "hello bye",
    "hello fred",
    "foo bar",
    "fred foo");

#calling the subroutine
my @ccomp = connected_component(@pairs);

use Data::Dumper;
print Dumper \@ccomp;

sub connected_component {

    my  @arr    = @_;
    my %links;

    foreach my $arrm (  @arr ) {
        my ($x,$y) = split(/\s+/,$arrm);;
        $links{$x}{$y} = $links{$y}{$x} = 1;

    }

    my %marked;  # nodes we have already visited
    my @stack;

    my @all_ccomp;

    my $connected_sub;
     $connected_sub = sub {
        no warnings 'recursion';
        my $node = shift;
        return if exists $marked{$node};  
        $marked{$node} = 1;
        push @stack, $node;  
        my $children = $links{$node};  
        &$connected_sub($_) for keys %$children;
    };

    for my $node (sort keys %links) { # Line 43
        next if exists $marked{$node};
        @stack = ();
        &$connected_sub($node);
        #print "@stack\n";
        push @all_ccomp, [@stack]; # Line 49
    }

    return @all_ccomp;
}

回答1:


As per perldoc's perldiag for that error, your problem is that the inner sub is referencing a lexical variable (%marked) defined in the outer sub.

The fix is in the third paragraph (use anonymous sub):

(Warning; closure) An inner (nested) named subroutine is referencing a lexical variable defined in an outer named subroutine.

When the inner subroutine is called, it will see the value of the outer subroutine's variable as it was before and during the first call to the outer subroutine; in this case, after the first call to the outer subroutine is complete, the inner and outer subroutines will no longer share a common value for the variable. In other words, the variable will no longer be shared.

This problem can usually be solved by making the inner subroutine anonymous, using the sub {} syntax. When inner anonymous subs that reference variables in outer subroutines are created, they are automatically rebound to the current values of such variables.

Fixed code using anonymous sub:

# ....
my $connected_sub;
$connected_sub = sub {
    no warnings 'recursion';
    my $node = shift;
    return if exists $marked{$node};  # Line 280
    $marked{$node} = 1;
    push @stack, $node;   # Line 282
    my $children = $links{$node};  # Line 283
    &$connected_sub($_) for keys %$children;
};

for my $node (sort keys %links) {
    next if exists $marked{$node};
    @stack = ();
    &$connected_sub($node);
    #print "@stack\n";
    push @all_ccomp, [@stack];
}
# ....



回答2:


Another (maybe simpler) way out is declare variables as "our" instead of "my"

So,

our %marked;

instead of

my %marked;

etc.




回答3:


When getting a diagnostic message from perl, it's usually a good idea to check out perldiag to find out what it means. That manpage also happens to cover the warning you're getting.

Basically, named subroutines don't nest in the way you were expecting them to. Solutions include using anonymous inner subroutines, not nesting named subroutines and just passing state on between them explicitly, or using something like mysubs from CPAN.




回答4:


This error can also happen if you've accidentally re-declared shared variables in the main thread of a script,

`

use vars qw(%types  %colors); 

my %types = (...);    # bad
%colors = (...);   # good

`



来源:https://stackoverflow.com/questions/4048248/variable-foo-will-not-stay-shared-warning-error-in-perl-while-calling-subrout

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!