how to write order by and limit query in jpa [duplicate]

问题

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Closed 7 years ago.

Possible Duplicate:
Select top 1 result using JPA

i wish to fetch top 10 results based on 'totalTradedVolume' filed of my table 'MasterScrip' when i write the following query:

Collection<MasterScrip> sm=null;
   sm=em.createQuery("select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2").setParameter("type", type).getResultList();

i get the following exception :

Caused by: java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: 
Exception Description: Syntax error parsing the query [select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2], line 1, column 78: unexpected token [limit].
Internal Exception: NoViableAltException(80@[])

something's wrong with my jpa query. can anyone pls correct me?

回答1:

limit is not recognized in JPA. You can instead use the query.setMaxResults method:

sm = em.createQuery("select m from MasterScrip m where m.type = :type 
        order by m.totalTradedVolume")
    .setParameter("type", type)
    .setMaxResults(2).getResultList()

回答2:

You can work it out with Query setFirstResult and setMaxResult methods

来源：https://stackoverflow.com/questions/10725469/how-to-write-order-by-and-limit-query-in-jpa