mySQL query returning Resource id #5

问题

I've searched about possible solutions to this. and I've tried looping as well as trying the variants of mysql_fetch_assoc and mysql_fetch_array but I'm still getting the Resource id #5: 0: error.

Here's my code which I think generates the error.

   <?php
            mysqlc();
            $email = GetSQLValueString($_SESSION['user'], "text");
            $query = sprintf("SELECT * FROM newmember WHERE email = %s",$email);
            $res = mysql_query($query) or die('Query failed: ' . mysql_error() . "<br />\n$sql");
            $row = mysql_fetch_assoc($res);
    ?>  

回答1:

"Resource id #5: 0" is not an error. It means that you tried to echo $res instead of trying to use the $row variable, such as $row[column] for fetch_assoc, $row[0] for fetch_row, either/both for fetch_array.

The other answers explain the use of mysql_fetch_*

Also, mysql_* is deprecated. You should use mysqli_* or PDO functions instead.

回答2:

Please use this one :

 while($row = mysql_fetch_object($res)){

              //do somthing 
              echo $row->name;

        }

I am already use this one in our code

回答3:

you need to use mysql_fetch_row

<?php
 $resultado = mysql_query("SELECT id, email FROM people WHERE id = '42'");
if (!$resultado) {
echo 'No se pudo ejecutar la consulta: ' . mysql_error();
 exit;
}
$fila = mysql_fetch_row($resultado);

echo $fila[0]; // 42
echo $fila[1]; // el valor de email
?>

来源：https://stackoverflow.com/questions/19142711/mysql-query-returning-resource-id-5