Why does 64-bit VC++ compiler add nop instruction after function calls?

丶灬走出姿态 提交于 2019-11-30 04:46:16

This is purely a guess, but it might be some kind of a SEH optimization. I say optimization because SEH seems to work fine without the NOPs too. NOP might help speed up unwinding.

In the following example (live demo with VC2017), there is a NOP inserted after a call to basic_string::assign in test1 but not in test2 (identical but declared as non-throwing1).

#include <stdio.h>
#include <string>

int test1() {
  std::string s = "a";  // NOP insterted here
  s += getchar();
  return (int)s.length();
}

int test2() throw() {
  std::string s = "a";
  s += getchar();
  return (int)s.length();
}

int main()
{
  return test1() + test2();
}

Assembly:

test1:
    . . .
    call     std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign
    npad     1         ; nop
    call     getchar
    . . .
test2:
    . . .
    call     std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign
    call     getchar

Note that MSVS compiles by default with the /EHsc flag (synchronous exception handling). Without that flag the NOPs disappear, and with /EHa (synchronous and asynchronous exception handling), throw() no longer makes a difference because SEH is always on.


1 For some reason only throw() seems to reduce the code size, using noexcept makes the generated code even bigger and summons even more NOPs. MSVC...

This is special filler to let exception handler/unwinding function to detect correctly whether it's prologue/epilogue/body of the function.

This is due to a calling convention in x64 which requires the stack to be 16 bytes aligned before any call instruction. This is not (to my knwoledge) a hardware requirement but a software one. This provides a way to be sure that when entering a function (that is, after a call instruction), the value of the stack pointer is always 8 modulo 16. Thus permitting simple data alignement and storage/reads from aligned location in stack.

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