Faster way of polygon intersection with shapely

问题

I have a large number of polygons (~100000) and try to find a smart way of calculating their intersecting area with a regular grid cells.

Currently, I am creating the polygons and the grid cells using shapely (based on their corner coordinates). Then, using a simple for-loop I go through each polygon and compare it to nearby grid cells.

Just a small example to illustrate the polygons/grid cells.

from shapely.geometry import box, Polygon
# Example polygon 
xy = [[130.21001, 27.200001], [129.52, 27.34], [129.45, 27.1], [130.13, 26.950001]]
polygon_shape = Polygon(xy)
# Example grid cell
gridcell_shape = box(129.5, -27.0, 129.75, 27.25)
# The intersection
polygon_shape.intersection(gridcell_shape).area

(BTW: the grid cells have the dimensions 0.25x0.25 and the polygons 1x1 at max)

Actually this is quite fast for an individual polygon/grid cell combo with around 0.003 seconds. However, running this code on a huge amount of polygons (each one could intersect dozens of grid cells) takes around 15+ minutes (up to 30+ min depending on the number of intersecting grid cells) on my machine which is not acceptable. Unfortunately, I have no idea how it is possible to write a code for polygon intersection to get the area of overlap. Do you have any tips? Is there an alternative to shapely?

回答1:

Consider using Rtree to help identify which grid cells that a polygon may intersect. This way, you can remove the for loop used with the array of lat/lons, which is probably the slow part.

Structure your code something like this:

from shapely.ops import cascaded_union
from rtree import index
idx = index.Index()

# Populate R-tree index with bounds of grid cells
for pos, cell in enumerate(grid_cells):
    # assuming cell is a shapely object
    idx.insert(pos, cell.bounds)

# Loop through each Shapely polygon
for poly in polygons:
    # Merge cells that have overlapping bounding boxes
    merged_cells = cascaded_union([grid_cells[pos] for pos in idx.intersection(poly.bounds)])
    # Now do actual intersection
    print poly.intersection(merged_cells).area

回答2:

It looks like the available The Shapely User Manual is rather out of date, but since 2013/2014, Shapely has had strtree.py with the class STRtree. I have used it and it seems to work well.

Here is a snippet from the docstring:

STRtree is an R-tree that is created using the Sort-Tile-Recursive algorithm. STRtree takes a sequence of geometry objects as initialization parameter. After initialization the query method can be used to make a spatial query over those objects.

>>> from shapely.geometry import Polygon
>>> polys = [ Polygon(((0, 0), (1, 0), (1, 1))), Polygon(((0, 1), (0, 0), (1, 0))), Polygon(((100, 100), (101, 100), (101, 101))) ]
>>> s = STRtree(polys)
>>> query_geom = Polygon(((-1, -1), (2, 0), (2, 2), (-1, 2)))
>>> result = s.query(query_geom)
>>> polys[0] in result
True

来源：https://stackoverflow.com/questions/14697442/faster-way-of-polygon-intersection-with-shapely

标签

python

numpy

shapely