MongoDB - Aggregation - To get unique items in array

送分小仙女□ 提交于 2019-11-30 04:13:37
Ananth

After few more tries, I had solved this. Here's the commands:

db.xyz.aggregate( {$project: {a: '$products.item'}}, 
    {$unwind: '$a'}, 
    {$unwind: '$a'}, 
    {$group: {_id: 'a', items: {$addToSet: '$a'}}});

and

db.xyz.aggregate( {$project: {category: 1, a: '$products.item'}}, 
    {$unwind: '$a'}, 
    {$unwind: '$a'}, 
    {$group: {_id: '$category', items: {$addToSet: '$a'}}});

I am not sure what you all you have tried in the aggregation function but i thought unwind will help you to do the same , assuming you are not able to get it done , we have a map-reduce which will allow you to easily do this one . You can look into the http://docs.mongodb.org/manual/applications/map-reduce/ . It allow you to get the data in a manner you want and you can easily get the list . I think $unwind on the tags column and then $group them will always give the us the list of distinct tags as required by you in 1 and for 2nd case create $group on two key category and item which was $unwind earlier.

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