opening a url with urllib in python 3

北慕城南 提交于 2019-11-30 03:19:11

You need to use from urllib.request import urlopen, also I suggest you use the with statement while opening a connection.

from urllib.request import urlopen

with urlopen("https://sunlightlabs.github.io/congress/legislators?api_key='(myapikey)") as conn:
    # dosomething

In Python 3 You can implement that this way:

import urllib.request
u = urllib.request.urlopen("xxxx")#The url you want to open

Pay attention: Some IDE can import urllib(Spyder) directly, while some need to import urllib.request(PyCharm).

That's because you sometimes need to explicitly import the pieces you want, so the module doesn't need to load everything up when you just want a small part of it.

Hope this will help.

Arnav Singh
from urllib.request import urlopen
from bs4 import BeautifulSoup

wiki = "https://en.wikipedia.org/wiki/List_of_state_and_union_territory_capitals_in_India"

page = urlopen(wiki)
soup =  BeautifulSoup(page, "html.parser" ).encode('UTF-8')

print (soup)
Fazil Ahmed

urllib.request is a module whereas urlopen is a function. check out this link, it can help you clear your doubts. https://docs.python.org/3.0/library/urllib.request.html

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