Run a function periodically in Scala

↘锁芯ラ 提交于 2019-11-29 22:55:23

You could use standard stuff from java.util.concurrent:

import java.util.concurrent._

val ex = new ScheduledThreadPoolExecutor(1)
val task = new Runnable { 
  def run() = println("Beep!") 
}
val f = ex.scheduleAtFixedRate(task, 1, 1, TimeUnit.SECONDS)
f.cancel(false)

Or java.util.Timer:

val t = new java.util.Timer()
val task = new java.util.TimerTask {
  def run() = println("Beep!") 
}
t.schedule(task, 1000L, 1000L)
task.cancel()

If you happen to be on Akka, Scheduler is quite convenient for this:

val system = ActorSystem("mySystem", config)
// ...now with system in current scope:
import system.dispatcher
system.scheduler.schedule(10 seconds, 1 seconds) {
  doSomeWork()
}

There is also scheduleOnce for one-off execution.

The usual warnings about closing over mutable state apply.

It can be more functional as in



    import java.util.TimerTask
    import java.util.Timer

    object TimerDemo {
      implicit def function2TimerTask(f: () => Unit): TimerTask = {
        return new TimerTask {
          def run() = f()
        }
      }

      def main(args : Array[String]) {
        def timerTask() = println("Inside timer task")

        val timer = new Timer()
        timer.schedule(function2TimerTask(timerTask),100, 10)

        Thread.sleep(5000)

        timer.cancel()

      }

    }

Update for Akka, in combination with the "Hello World example" from here: Lightbend Guides using the instructions from here: Scheduler

import scala.concurrent.duration._

howdyGreeter ! WhoToGreet("Akka")

val cancellable =
system.scheduler.schedule(
  0 seconds,
  1 seconds,
  howdyGreeter,
  Greet
)
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!