MySQL joins and COUNT(*) from another table

℡╲_俬逩灬. 提交于 2019-11-29 22:53:29
Nazariy

MySQL use HAVING statement for this tasks.

Your query would look like this:

SELECT g.group_id, COUNT(m.member_id) AS members
FROM groups AS g
LEFT JOIN group_members AS m USING(group_id)
GROUP BY g.group_id
HAVING members > 4

example when references have different names

SELECT g.id, COUNT(m.member_id) AS members
FROM groups AS g
LEFT JOIN group_members AS m ON g.id = m.group_id
GROUP BY g.id
HAVING members > 4

Also, make sure that you set indexes inside your database schema for keys you are using in JOINS as it can affect your site performance.

Reena Shirale
SELECT DISTINCT groups.id, 
       (SELECT COUNT(*) FROM group_members
        WHERE member_id = groups.id) AS memberCount
FROM groups
bbb

Your groups_main table has a key column named id. I believe you can only use the USING syntax for the join if the groups_fans table has a key column with the same name, which it probably does not. So instead, try this:

LEFT JOIN groups_fans AS m ON m.group_id = g.id

Or replace group_id with whatever the appropriate column name is in the groups_fans table.

Maybe I am off the mark here and not understanding the OP but why are you joining tables?

If you have a table with members and this table has a column named "group_id", you can just run a query on the members table to get a count of the members grouped by the group_id.

SELECT group_id, COUNT(*) as membercount 
FROM members 
GROUP BY group_id 
HAVING membercount > 4

This should have the least overhead simply because you are avoiding a join but should still give you what you wanted.

If you want the group details and description etc, then add a join from the members table back to the groups table to retrieve the name would give you the quickest result.

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