Remove item from a Makefile variable?

走远了吗. 提交于 2019-11-29 22:45:58
Mat

You could use the filter-out text function if you're using GNU Make.

OTHERVAR := $(filter-out SomethingElse,$(VAR))

On top of the correct answer above:

VAR = bla1 bla2 bla3 bla4 bla5

TMPVAR := $(VAR)
VAR = $(filter-out bla3, $(TMPVAR))

all:
    @echo "VAR is: $(VAR)"

Output:
VAR is: bla1 bla2 bla4 bla5

Note that this breaks all "recursivity" when filter-out is executed, but that might not matter in your case.

As I also have a similar situation, I want to add a new answer. In my case there were also commas into the variable string and, more, I wanted to remove the comma and the last word :

VAR = "bla1, bla2"

In this case filter out is not working (not even in the previous answers, when there are no quotes)

My solution is to use subst :

VAR = "bla1, bla2"

TTT = , bla2
TMPVAR := $(VAR)
SUBST = $(subst $(TTT),, $(TMPVAR))
FILT = $(filter-out $(TTT), $(TMPVAR))

subst:
    @echo "subst : $(SUBST)"

filter:
    @echo "filter-out : $(FILT)"
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