This question already has an answer here:
- Calling a phone number in swift 20 answers
I want my app to be able to call a certain number when a button is clicked. I've tried to google it but there doesn't seem to have one for iOS 10 so far (where openURL is gone). Can someone put an example for me on how to do so? For instance like:
@IBAction func callPoliceButton(_ sender: UIButton) {
// Call the local Police department
}
You can call like this:
if let url = URL(string: "tel://\(number)") {
UIApplication.shared.openURL(url)
}
For Swift 3+, you can use like
guard let number = URL(string: "tel://" + number) else { return }
UIApplication.shared.open(number)
OR
UIApplication.shared.open(number, options: [:], completionHandler: nil)
Make sure you've scrubbed your phone number string to remove any instances of (, ), -, or space.
Task
Make a call with phone number validation
Details
Tested on:
- Xcode 9.2, Swift 4
- Xcode 10.2 (10E125), Swift 5
Solution
extension String {
func extractAll(type: NSTextCheckingResult.CheckingType) -> [NSTextCheckingResult] {
var result = [NSTextCheckingResult]()
do {
let detector = try NSDataDetector(types: type.rawValue)
result = detector.matches(in: self, range: NSRange(startIndex..., in: self))
} catch { print("ERROR: \(error)") }
return result
}
func to(type: NSTextCheckingResult.CheckingType) -> String? {
let phones = extractAll(type: type).compactMap { $0.phoneNumber }
switch phones.count {
case 0: return nil
case 1: return phones.first
default: print("ERROR: Detected several phone numbers"); return nil
}
}
func onlyDigits() -> String {
let filtredUnicodeScalars = unicodeScalars.filter{CharacterSet.decimalDigits.contains($0)}
return String(String.UnicodeScalarView(filtredUnicodeScalars))
}
func makeAColl() {
guard let number = to(type: .phoneNumber),
let url = URL(string: "tel://\(number.onlyDigits())"),
UIApplication.shared.canOpenURL(url) else { return }
if #available(iOS 10, *) {
UIApplication.shared.open(url)
} else {
UIApplication.shared.openURL(url)
}
}
}
Usage
"+1-(800)-123-4567".makeAColl()
"phone:+1(617)111-22-33!".makeAColl() // Will extract "+1(617)111-22-33" and make a call
let text = "blabla, +1(222)333-44-55, dasdwedsczx acscas 123-89-01"
let phones = text.extractAll(type: .phoneNumber).compactMap { $0.phoneNumber }
print(phones)
Full sample
func test() {
isPhone("blabla")
isPhone("+1(222)333-44-55")
isPhone("+42 555.123.4567")
isPhone("+1-(800)-123-4567")
isPhone("+7 555 1234567")
isPhone("+7(926)1234567")
isPhone("(926) 1234567")
isPhone("+79261234567")
isPhone("926 1234567")
isPhone("9261234567")
isPhone("1234567")
isPhone("123-4567")
isPhone("123-89-01")
isPhone("495 1234567")
isPhone("469 123 45 67")
isPhone("8 (926) 1234567")
isPhone("89261234567")
isPhone("926.123.4567")
isPhone("415-555-1234")
isPhone("650-555-2345")
isPhone("(416)555-3456")
isPhone("202 555 4567")
isPhone("4035555678")
isPhone(" 1 416 555 9292")
isPhone("+44 1838 300284")
isPhone("+44 1838 300284, 1 416 555 9292")
}
private func isPhone(_ string: String) {
let result = string.to(type: .phoneNumber) != nil
print("\(result ? "✅" : "❌") \(string) | \(string.onlyDigits()) | \(result ? "[a phone number]" : "[not a phone number]")")
}
Result
❌ blabla | | [not a phone number]
✅ +1(222)333-44-55 | 12223334455 | [a phone number]
✅ +42 555.123.4567 | 425551234567 | [a phone number]
✅ +1-(800)-123-4567 | 18001234567 | [a phone number]
✅ +7 555 1234567 | 75551234567 | [a phone number]
✅ +7(926)1234567 | 79261234567 | [a phone number]
✅ (926) 1234567 | 9261234567 | [a phone number]
✅ +79261234567 | 79261234567 | [a phone number]
✅ 926 1234567 | 9261234567 | [a phone number]
✅ 9261234567 | 9261234567 | [a phone number]
✅ 1234567 | 1234567 | [a phone number]
✅ 123-4567 | 1234567 | [a phone number]
✅ 123-89-01 | 1238901 | [a phone number]
✅ 495 1234567 | 4951234567 | [a phone number]
✅ 469 123 45 67 | 4691234567 | [a phone number]
✅ 8 (926) 1234567 | 89261234567 | [a phone number]
✅ 89261234567 | 89261234567 | [a phone number]
✅ 926.123.4567 | 9261234567 | [a phone number]
✅ 415-555-1234 | 4155551234 | [a phone number]
✅ 650-555-2345 | 6505552345 | [a phone number]
✅ (416)555-3456 | 4165553456 | [a phone number]
✅ 202 555 4567 | 2025554567 | [a phone number]
✅ 4035555678 | 4035555678 | [a phone number]
✅ 1 416 555 9292 | 14165559292 | [a phone number]
✅ +44 1838 300284 | 441838300284 | [a phone number]
ERROR: Detected several phone numbers
❌ +44 1838 300284, 1 416 555 9292 | 44183830028414165559292 | [not a phone number]
["+1(222)333-44-55", "123-89-01"]
Updated for Swift 3:
used below simple lines of code, if you want to make a phone call:
// function defination:
func makeAPhoneCall() {
let url: NSURL = URL(string: "TEL://1234567890")! as NSURL
UIApplication.shared.open(url as URL, options: [:], completionHandler: nil)
}
// function call: [Used anywhere in your code]
self.makeAPhoneCall()
Note: Please run the app on a real device because it won't work on the simulator.
In Swift 4.2
func dialNumber(number : String) {
if let url = URL(string: "tel://\(number)"),
UIApplication.shared.canOpenURL(url) {
if #available(iOS 10, *) {
UIApplication.shared.open(url, options: [:], completionHandler:nil)
} else {
UIApplication.shared.openURL(url)
}
} else {
// add error message here
}
}
Call this like below
dialNumber(number: "+921111111222")
Hope this help.
if let phoneCallURL:URL = URL(string: "tel:\(strPhoneNumber)") {
let application:UIApplication = UIApplication.shared
if (application.canOpenURL(phoneCallURL)) {
let alertController = UIAlertController(title: "MyApp", message: "Are you sure you want to call \n\(self.strPhoneNumber)?", preferredStyle: .alert)
let yesPressed = UIAlertAction(title: "Yes", style: .default, handler: { (action) in
application.openURL(phoneCallURL)
})
let noPressed = UIAlertAction(title: "No", style: .default, handler: { (action) in
})
alertController.addAction(yesPressed)
alertController.addAction(noPressed)
present(alertController, animated: true, completion: nil)
}
}
By mistake my answer was misplaced, please checkout this one: You can use this:
guard let url = URL(string: "tel://\(yourNumber)") else {
return //be safe
}
if #available(iOS 10.0, *) {
UIApplication.shared.open(url)
} else {
UIApplication.shared.openURL(url)
}
We need to check whether we're on iOS 10 or later As 'openURL' was deprecated in iOS 10.0
来源：https://stackoverflow.com/questions/40078370/how-to-make-phone-call-in-ios-10-using-swift