How to deal with rounding errors in Shapely

限于喜欢 提交于 2019-11-29 18:31:03

问题


I have a case which is based on projecting a point on a line and then separate this line on it. My use case is slightly more complicated, but my problem can be reproduced with the following code:

from shapely import *
line1 = LineString([(1,1.2), (2,2), (3, 2.), (4,1.2)])
pt = Point(2.5, 1.2)
pr = line1.interpolate(line1.project(pt))

By construction, "pr" should be on line1 and their intersection too:

line1.contains(pr)
line1.intersects(LineString([pt, pr]))

prints two times "True". But changing the input coordinates slightly brakes the workflow:

from shapely import *
line1 = LineString([(1,1.2), (2,2), (3, 2.3), (4,1.2)])
pt = Point(2.5, 1.2)
pr = line1.interpolate(line1.project(pt))
line1.contains(pr)
line1.intersects(LineString([pt, pr]))

prints "False".

I understand the floating precision problem behind this, but does that mean that I can never test for points being on lines? When I construct a line based on a list of points, can I be sure that at least all the "construction" points will be on the line?


回答1:


Fundamentally, a precision model is needed, and there are various plans to implement this into GEOS at some time (don't hold your breath, as this has been under discussion for several years).

Otherwise, the options are distance-based tests (recommended) or more expensive buffer-based techniques by a small adjustment (see machine epsilon):

from shapely.geometry import LineString, Point

line1 = LineString([(1, 1.2), (2, 2), (3, 2.3), (4, 1.2)])
pt = Point(2.5, 1.2)
pr = line1.interpolate(line1.project(pt))

# Distance based
print(line1.distance(pr) == 0.0)  # True

# Buffer based
EPS = 1.2e-16
print(line1.buffer(EPS).contains(pr))  # True
print(line1.buffer(EPS).intersects(LineString([pt, pr])))  # True

You can also chain cheaper and expensive tests using an or operator, for example:

print(line1.contains(pr) or line1.buffer(EPS).contains(pr))

which only runs the second and more expensive test if the first one returns False.



来源:https://stackoverflow.com/questions/28028910/how-to-deal-with-rounding-errors-in-shapely

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!