问题
I\'m writing a ruby bootstrapping script for a school project, and part of this bootstrapping process is to start a couple of background processes (which are written and function properly). What I\'d like to do is something along the lines of:
`/path/to/daemon1 &`
`/path/to/daemon2 &`
`/path/to/daemon3 &`
However, that blocks on the first call to execute daemon1. I\'ve seen references to a Process.spawn method, but that seems to be a 1.9+ feature, and I\'m limited to Ruby 1.8.
I\'ve also tried to execute these daemons from different threads, but I\'d like my bootstrap script to be able to exit.
So how can I start these background processes so that my bootstrap script doesn\'t block and can exit (but still have the daemons running in the background)?
回答1:
As long as you are working on a POSIX OS you can use fork and exec.
fork = Create a subprocess
exec = Replace current process with another process
You then need to inform that your main-process is not interested in the created subprocesses via Process.detach.
job1 = fork do
exec "/path/to/daemon01"
end
Process.detach(job1)
...
回答2:
better way to pseudo-deamonize:
`((/path/to/deamon1 &)&)`
will drop the process into it's own shell.
best way to actually daemonize:
`service daemon1 start`
and make sure the server/user has permission to start the actual daemon. check out 'deamonize' tool for linux to set up your deamon.
来源：https://stackoverflow.com/questions/2504445/spawn-a-background-process-in-ruby