问题
I get java.lang.IllegalArgumentException: bad base-64 while trying to use Base64 on Android 1.5
private static String encrypt(Context cont, String value) {
try {
return Base64.encodeToString(value.getBytes(), Base64.DEFAULT);
} catch (Exception e) {
throw new RuntimeException(e);
}
}
private static String decrypt(Context cont, String value) {
try {
return new String(Base64.decode(value, Base64.DEFAULT));
} catch (Exception e) {
throw new RuntimeException(e);
}
}
/*
* Copyright (C) 2010 The Android Open Source Project
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
}
Caused by: java.lang.IllegalArgumentException: bad base-64
at: Base64.decode(Base64.java:161)
回答1:
public class Crypto {
public static String encrypt(String value, String key) throws GeneralSecurityException {
SecretKeySpec sks = new SecretKeySpec(hexStringToByteArray(key), "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.ENCRYPT_MODE, sks, cipher.getParameters());
byte[] encrypted = cipher.doFinal(value.getBytes());
return byteArrayToHexString(encrypted);
}
public static String decrypt(String message, String key) throws GeneralSecurityException {
SecretKeySpec sks = new SecretKeySpec(hexStringToByteArray(key), "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.DECRYPT_MODE, sks);
byte[] decrypted = cipher.doFinal(hexStringToByteArray(message));
return new String(decrypted);
}
private static String byteArrayToHexString(byte[] b){
StringBuffer sb = new StringBuffer(b.length * 2);
for (int i = 0; i < b.length; i++){
int v = b[i] & 0xff;
if (v < 16) {
sb.append('0');
}
sb.append(Integer.toHexString(v));
}
return sb.toString().toUpperCase();
}
private static byte[] hexStringToByteArray(String s) {
byte[] b = new byte[s.length() / 2];
for (int i = 0; i < b.length; i++){
int index = i * 2;
int v = Integer.parseInt(s.substring(index, index + 2), 16);
b[i] = (byte)v;
}
return b;
}
}
above class will help in encrypt and decrypt string without base64
usage of above class
try {
String key = UUID.randomUUID().toString().replaceAll("-", "");
String src = "Hello world!";
String tag1 = Crypto.encrypt(src, key);
String tag2 = Crypto.decrypt(tag1, key);
logger.info(src);
logger.info(tag1);
logger.info(tag2);
} catch (Exception e) {
logger.error("", e);
}
回答2:
private static String encrypt(Context cont, String value) {
try {
return Base64.encodeToString(value.getBytes(), Base64.DEFAULT);
}
catch (IllegalArgumentException e) {
// TODO: handle exception
}
catch (Exception e) {
throw new RuntimeException(e);
}
}
private static String decrypt(Context cont, String value) {
try {
return new String(Base64.decode(value, Base64.DEFAULT));
}
catch (IllegalArgumentException e) {
// TODO: handle exception
}
catch (Exception e) {
throw new RuntimeException(e);
}
}
add illegal argument exception catch ..... I hope it will work
回答3:
have you seen this ?
How to encode a string with Base64 in Android?
They are using Base64 Library from iHarder.net to encode/decode strings
来源：https://stackoverflow.com/questions/13066762/illegalargumentexception-bad-base-64-while-trying-to-use-base64-on-android-1