How to read local xml file is resource folder as a input stream in android?

问题

I am trying to get input stream from something like this.

InputSource myInputSource = new InputSource(activity.getResources().openRawResource(com.MYCLass.R.xml.programs));

myXMLReader.parse(myInputSource);

and then call parse on the parser instance i Created. Some how i get nothing.
Works fine if I use a server XML....

回答1:

Put the xml file into /res/raw folder. It looks like openRawResource opens resources from that folder only. You can also try getResources().getXml(com.MYCLass.R.xml.programs); which will return you an instance of XML parser.

A piece of code taken from @Krupa

InputStream object = this.getResources()
                     .openRawResource(R.raw.fileName);

回答2:

You can read the file by the following code :

InputStream object = this.getResources()
        .openRawResource(R.rawFolderName.fileName);

来源：https://stackoverflow.com/questions/3464307/how-to-read-local-xml-file-is-resource-folder-as-a-input-stream-in-android