Force SymPy to keep the order of terms

Question

I have the following code:

from sympy import *
init_printing()

x,y = symbols('x y')
u = Function('u')(x,y)
ux,uy,uxx,uxy,uyy = symbols("u_x u_y u_xx u_xy u_yy")

mainEvaluation = uxx - 2*sin(x)*uxy - (cos(x) ** 2) * uyy - 2*ux + (2 - cos(x) + 2*sin(x) )*uy

And when the output of print(mainExpression) is

-2*u_x + u_xx - 2*u_xy*sin(x) + u_y*(2*sin(x) - cos(x) + 2) - u_yy*cos(x)**2

The problem is: I want the original order of variables.

u_xx - 2*u_xy*sin(x)  - u_yy*cos(x)**2  - 2*u_x + u_y*(2*sin(x) - cos(x) + 2)

All this is done in IPython notebook. Is there any way to keep order?

Answer 1

Sadly, SymPy does not keep track of the input order (see the other question I linked in a comment on the question). You can define your own ordering function that orders expressions however you want, but there's no way to order things exactly as they were input, since that information isn't saved.

Answer 2

try read this http://docs.sympy.org/0.7.2/modules/utilities/misc.html, may be could help you

Note:

The key returned is useful for getting items into a canonical order that will be the same across platforms. It is not directly useful for sorting lists of expressions:

>>> a, b = x, 1/x

Since a has only 1 term, its value of sort_key is unaffected by order:

>>> a.sort_key() == a.sort_key('rev-lex')
True

If a and b are combined then the key will differ because there are terms that can be ordered:

>>> eq = a + b
>>> eq.sort_key() == eq.sort_key('rev-lex')
False
>>> eq.as_ordered_terms()
[x, 1/x]
>>> eq.as_ordered_terms('rev-lex')
[1/x, x]

But since the keys for each of these terms are independent of order‘s value, they don’t sort differently when they appear separately in a list:

>>> sorted(eq.args, key=default_sort_key)
[1/x, x]
>>> sorted(eq.args, key=lambda i: default_sort_key(i, order='rev-lex'))
[1/x, x]

The order of terms obtained when using these keys is the order that would be obtained if those terms were factors in a product.

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