Django - How to make a variable available to all templates?

问题

I would like to know how to pass a variable to all my templates, without repeating the same code on every method in my views.py file?

In the example below I would like to make categories (an array of category objects) available to all templates in the web app.

Eg: I would like to avoid writing \'categories\':categories on every method. Is it possible?

One view method

def front_page(request):
    categories = Category.objects.all()
    if is_logged_in(request) is False:
        return render_to_response(\'users/signup.html\', {\'is_logged_in\': is_logged_in(request), \'categories\':categories}, context_instance=RequestContext(request))
    else:
        return render_to_response(\'users/front_page.html\', {\'is_logged_in\': is_logged_in(request), \'categories\':categories},context_instance=RequestContext(request))

Another view method

def another_view_method(request):
    categories = Category.objects.all()
    return render_to_response(\'eg/front_page.html\', {\'is_logged_in\': is_logged_in(request), \'categories\':categories},context_instance=RequestContext(request))

回答1:

What you want is a context processor, and it's very easy to create one. Assuming you have an app named custom_app, follow the next steps:

Add custom_app to INSTALLED_APPS in settings.py (you've done it already, right?);
Create a context_processors.py into custom_app folder;

Add the following code to that new file:

def categories_processor(request):
 categories = Category.objects.all()            
 return {'categories': categories}

Add context_processors.py to TEMPLATE_CONTEXT_PROCESSORS in settings.py

TEMPLATE_CONTEXT_PROCESSORS += ("custom_app.context_processors.categories_processor", )

And now you can use {{categories}} in all the templates :D

As of Django 1.8

To add a TEMPLATE_CONTEXT_PROCESSORS, in the settings you must add the next code:

TEMPLATES[0]['OPTIONS']['context_processors'].append("custom_app.context_processors.categories_processor")

Or include that string directly in the OPTIONS.context_processors key in your TEMPLATES setting.

回答2:

As seen in this example, post Django 1.3 you can simply use render instead of render_to_response which doesn't require you to explicitly pass the context processor.

def another_view_method(request):
    categories = Category.objects.all()
    return render(
        'eg/front_page.html',
        {'is_logged_in': is_logged_in(request), 'categories':categories}
    )

来源：https://stackoverflow.com/questions/17901341/django-how-to-make-a-variable-available-to-all-templates

标签

python

django

django-nonrel