While looking through some c header files (specifically stdarg.h), I noticed a very peculiar line:
#if !defined(__STRICT_ANSI__) || __STDC_VERSION__ + 0 >= 199900L
The strange part is the + 0. Zero is the additive identity; it's one of the various math has of writing noop.
What purpose does adding zero have in the above preprocessor statement? I know that there's all sorts of weird preprocessor magic out there, but this just seems ridiculous.
That avoids a preprocessor syntax error if __STDC_VERSION__ is defined as an
empty token (e.g. with #define __STDC_VERSION__).
(Thanks to Jens Gustedt for pointing out that the first version of my answer was wrong.)
来源：https://stackoverflow.com/questions/20448053/adding-zero-in-c-preprocessor-statement