Access request in django custom template tags

爷,独闯天下 提交于 2019-11-26 09:16:17

问题


My code in myapp_extras.py:

from django import template

register = template.Library()

@register.inclusion_tag(\'new/userinfo.html\')
def address():
    address = request.session[\'address\']
    return {\'address\':address}

in \'settings.py\':

TEMPLATE_CONTEXT_PROCESSORS =(
    \"django.core.context_processors.auth\",
    \"django.core.context_processors.debug\",
    \"django.core.context_processors.i18n\",
    \"django.core.context_processors.media\",
    \'django.core.context_processors.request\'
)

but I got an error:

TemplateSyntaxError at /items/

Caught an exception while rendering: global name \'request\' is not defined

Original Traceback (most recent call last):
  File \"C:\\Python25\\lib\\site-packages\\django\\template\\debug.py\", line 71, in render_node
    result = node.render(context)
  File \"C:\\Python25\\lib\\site-packages\\django\\template\\__init__.py\", line 915, in render
    dict = func(*args)
  File \"C:\\p4\\projects\\myproject\\..\\myproject\\invoice\\templatetags\\myapp_extras.py\", line 9, in address
    address = request.session[\'address\']
NameError: global name \'request\' is not defined

I referenced this one In Django, is it possible to access the current user session from within a custom tag?.


回答1:


request is not a variable in that scope. You will have to get it from the context first. Pass takes_context to the decorator and add context to the tag arguments.

Like this:

@register.inclusion_tag('new/userinfo.html', takes_context=True)
def address(context):
    request = context['request']
    address = request.session['address']
    return {'address':address}



回答2:


I've tried solution from above (from Ignacio Vazquez-Abrams) and it actually didn't work until I've found out that context processors works only with RequestContext wrapper class.

So in main view method you should add the following line:

from django.template import RequestContext        
return render_to_response('index.html', {'form': form, }, 
                              context_instance = RequestContext(request))



回答3:


I've done this way:

from django import template
register = template.Library()

def do_test_request(parser,token):
    try:
        tag_name = token.split_contents() # Not really useful
    except ValueError:
        raise template.TemplateSyntaxError("%r error" % token.contents.split()[0])
    return RequestTestNode()

class RequestTestNode(template.Node):
    def __init__(self,):
        self.request = template.Variable('request')
    def render(self, context):
        rqst = self.request.resolve(context)
        return "The URL is: %s" % rqst.get_full_path()

register.tag('test_request', do_test_request)

There is also a function called resolve_variable, but it's deprecated.

Hope it helps!



来源:https://stackoverflow.com/questions/2160261/access-request-in-django-custom-template-tags

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