numpy function to set elements of array to a value given a list of indices

问题

I'm looking for a numpy function that will do the equivalent of:

indices = set([1, 4, 5, 6, 7])
zero    = numpy.zeros(10)
for i in indices:
    zero[i] = 42

回答1:

You can just give it a list of indices:

indices = [1, 4, 5, 6, 7]
zero = numpy.zeros(10)
zero[indices] = 42

回答2:

If you have an ndarry:

>>> x = np.zeros((3, 3, 3))
>>> y = [0, 9, 18]
>>> x
array([[[ 0.,  0.,  0.],
       [ 0.,  0.,  0.],
       [ 0.,  0.,  0.]],

      [[ 0.,  0.,  0.],
       [ 0.,  0.,  0.],
       [ 0.,  0.,  0.]],

      [[ 0.,  0.,  0.],
       [ 0.,  0.,  0.],
       [ 0.,  0.,  0.]]])
>>> np.put(x, y,  1)
>>> x
array([[[ 1.,  0.,  0.],
        [ 0.,  0.,  0.],
        [ 0.,  0.,  0.]],

       [[ 1.,  0.,  0.],
        [ 0.,  0.,  0.],
        [ 0.,  0.,  0.]],

       [[ 1.,  0.,  0.],
        [ 0.,  0.,  0.],
        [ 0.,  0.,  0.]]])

来源：https://stackoverflow.com/questions/8373079/numpy-function-to-set-elements-of-array-to-a-value-given-a-list-of-indices