问题
Here is my cat /proc/cpuinfo
output:
...
processor : 15
vendor_id : GenuineIntel
cpu family : 6
model : 26
model name : Intel(R) Xeon(R) CPU E5520 @ 2.27GHz
stepping : 5
cpu MHz : 1600.000
cache size : 8192 KB
physical id : 1
siblings : 8
core id : 3
cpu cores : 4
apicid : 23
fpu : yes
fpu_exception : yes
cpuid level : 11
wp : yes
flags : fpu vme de pse tsc msr pae mce cx8 apic ...
bogomips : 4533.56
clflush size : 64
cache_alignment : 64
address sizes : 40 bits physical, 48 bits virtual
power management :
This machine has two CPUs, each with 4 cores with hyperthreading capability, so the total processor number is 16(2 CPU * 4 core * 2 hyperthreading). These processors have same output, to keep clean, I just show the last one's info and omit part of flags in the flags line.
So how do I calculate the peak performance of this machine in terms of GFlops? Let me know if more info should be supplied.
Thanks.
回答1:
You can check the Intel export spec. The GFLOP in the chart is usually referred as the peak of a single chip. It shows 36.256 Gflop/s for E5520.
This single chip has 4 physical cores with SSE. So this GFLOP can also be calculated as: 2.26GHz*2(mul,add)*2(SIMD double precision)*4(physical core) = 36.2.
You system has two CPUs, so your peak is 36.2*2 = 72.4 GFLOP/S.
回答2:
you can find a formula in this website:
http://www.novatte.com/our-blog/197-how-to-calculate-peak-theoretical-performance-of-a-cpu-based-hpc-system
here the formula:
performance in GFlops = (CPU speed in GHz) x (number of CPU cores) x (CPU instruction per cycle) x (number of CPUs per node).
so in your case: 2.27x4x4x2=72.64 GFLOP/s see here for the configuration of your CPU http://ark.intel.com/products/40200
来源:https://stackoverflow.com/questions/6289745/how-to-compute-the-theoretical-peak-performance-of-cpu