Can a JavaScript function return itself?

吃可爱长大的小学妹 提交于 2019-11-29 05:27:43

There are 2-3 ways. One is, as you say, is to use arguments.callee. It might be the only way if you're dealing with an anonymous function that's not stored assigned to a variable somewhere (that you know of):

(function() {
    return arguments.callee;
})()()()().... ;

The 2nd is to use the function's name

function namedFunc() {
    return namedFunc;
}
namedFunc()()()().... ;

And the last one is to use an anonymous function assigned to a variable, but you have to know the variable, so in that case I see no reason, why you can't just give the function a name, and use the method above

var storedFunc = function() {
    return storedFunc;
};
storedFunc()()()().... ;

They're all functionally identical, but callee is the simplest.

Edit: And I agree with SLaks; I can't recommend it either

Yes.
Just return arguments.callee;


However, this is likely to result in very confusing code; I do not recommend it.

ataru

You can do what you want as following:

// Do definition and execution at the same time.
var someFunction = (function someFunction() {

    // do stuff
    return someFunction
 })();

 console.log(someFunction)

arguments.callee is not supported in JavaScript strict mode.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Strict_mode

There is a simple way to achieve this doing the following:

let intArr = [];
function mul(x){
    if(!x){
        return intArr.reduce((prev, curr) => prev * curr)
    }
    intArr.push(x);
    return mul;
}

console.log(mul(2)(4)(2)()); => outputs 16

It is also possible just to return the argument the self invokable function like

console.log( (function(a) {  return a; })(1) ); // returns 1

Even sorter that all the above is:

f=()=>f
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