How to get the first name and last name from Android contacts?

Question

How to get the following fields from Android contacts? I used Android 2.2.

1. Name prefix
2. First name
3. Middle name
4. Last name
5. Name prefix
6. Phonetic given name
7. Phonetic middle name
8. Phonetic family name

Answer 1

Look at ContactsContract.CommonDataKinds.StructuredName class. You can find there all columns you are looking for. Try sth like this:

    String whereName = ContactsContract.Data.MIMETYPE + " = ?";
    String[] whereNameParams = new String[] { ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE };
    Cursor nameCur = contentResolver.query(ContactsContract.Data.CONTENT_URI, null, whereName, whereNameParams, ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
    while (nameCur.moveToNext()) {
        String given = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME));
        String family = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
        String display = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME));
    }
    nameCur.close();

It returns all names in contacts. To be more precise you can add a contact id as an additional parameter to the query - you will get address for particular contact.

Answer 2

For a specified contact you can do this :

String whereName = ContactsContract.Data.MIMETYPE + " = ? AND " + ContactsContract.CommonDataKinds.StructuredName.CONTACT_ID + " = ?";
String[] whereNameParams = new String[] { ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE, contact_ID };
Cursor nameCur = contentResolver.query(ContactsContract.Data.CONTENT_URI, null, whereName, whereNameParams, ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
while (nameCur.moveToNext()) {
    String given = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME));
    String family = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
    String display = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME));
}
nameCur.close();

Answer 3

try to use this code to get the required information about the contact,the code is here-

import android.provider.ContactsContract.Contacts;
import android.database.Cursor;

// Form an array specifying which columns to return, you can add more.
String[] projection = new String[] {
                         ContactsContract.Contacts.DISPLAY_NAME,
                         ContactsContract.CommonDataKinds.Phone
                         ContactsContract.CommonDataKinds.Email
                      };

Uri contacts =  ContactsContract.Contacts.CONTENT_LOOKUP_URI;
// id of the Contact to return.
long id = 3;

// Make the query. 
Cursor managedCursor = managedQuery(contacts,
                     projection, // Which columns to return 
                     null,       // Which rows to return (all rows)
                                 // Selection arguments (with a given ID)
                     ContactsContract.Contacts._ID = "id", 
                                 // Put the results in ascending order by name
                     ContactsContract.Contacts.DISPLAY_NAME + " ASC");

Answer 4

As the other example (just for fun) but for fetching contact name of a single user:

// A contact ID is fetched from ContactList
Uri resultUri = data.getData(); 
Cursor cont = getContentResolver().query(resultUri, null, null, null, null);
if (!cont.moveToNext()) {   
    Toast.makeText(this, "Cursor contains no data", Toast.LENGTH_LONG).show(); 
                return;
}
int columnIndexForId = cont.getColumnIndex(ContactsContract.Contacts._ID);
String contactId = cont.getString(columnIndexForId);

// Fetch contact name with a specific ID
String whereName = ContactsContract.Data.MIMETYPE + " = ? AND " + ContactsContract.CommonDataKinds.StructuredName.CONTACT_ID + " = " + contactId; 
String[] whereNameParams = new String[] { ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE };
Cursor nameCur = getContentResolver().query(ContactsContract.Data.CONTENT_URI, null, whereName, whereNameParams, ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME);
while (nameCur.moveToNext()) {
    String given = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.GIVEN_NAME));
    String family = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME));
    String display = nameCur.getString(nameCur.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME));
    Toast.makeText(this, "Name: " + given + " Family: " +  family + " Displayname: "  + display, Toast.LENGTH_LONG).show();
}
nameCur.close();
cont.close();

Answer 5

Some links to get you started, in addition to the suggestions from Raunak:

• http://www.higherpass.com/Android/Tutorials/Working-With-Android-Contacts/
• How to obtain all details of a contact in Android
• http://developer.android.com/resources/samples/ContactManager/index.html

Answer 6

Experimenting with the ContactsContract.Data.CONTENT_URI in late 2015 on marshmallow. I'm unable to get the GIVEN_NAME or similar fields. I think the later apis have deprecated these. Run the following code to print out the columns you have on your phone

Uri uri = ContactsContract.Data.CONTENT_URI;
String selection = ContactsContract.Data.MIMETYPE + " = ?";
String[] selectionArgs = new String[] { ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE};
Cursor cursor = contentResolver.query(
            uri,       // URI representing the table/resource to be queried
            null,      // projection - the list of columns to return.  Null means "all"
            selection, // selection - Which rows to return (condition rows must match)
            selectionArgs,      // selection args - can be provided separately and subbed into selection.
            null);   // string specifying sort order

if (cursor.getCount() == 0) {
  return;
}
Log.i("Count:", Integer.toString(cursor.getCount())); // returns number of names on phone

while (cursor.moveToNext()) {
  // Behold, the firehose!
  Log.d(TAG, "-------------------new record\n");
  for(String column : cursor.getColumnNames()) {
    Log.d(TAG, column + ": " + cursor.getString(cursor.getColumnIndex(column)) + "\n");
  }
}

Answer 7

try this,

public void onActivityResult(int reqCode, int resultCode, Intent data) { super.onActivityResult(reqCode, resultCode, data);

    try {
        if (resultCode == Activity.RESULT_OK) {
            Uri contactData = data.getData();
            Cursor cur = managedQuery(contactData, null, null, null, null);
            ContentResolver contect_resolver = getContentResolver();

            if (cur.moveToFirst()) {
                String id = cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
                String name = "";
                String no = "";

                Cursor phoneCur = contect_resolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null);

                if (phoneCur.moveToFirst()) {
                    name = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    no = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                }

                Log.e("Phone no & name :***: ", name + " : " + no);
                txt.append(name + " : " + no + "\n");

                id = null;
                name = null;
                no = null;
                phoneCur = null;
            }
            contect_resolver = null;
            cur = null;
            //                      populateContacts();
        }
    } catch (IllegalArgumentException e) {
        e.printStackTrace();
        Log.e("IllegalArgumentException::", e.toString());
    } catch (Exception e) {
        e.printStackTrace();
        Log.e("Error :: ", e.toString());
    }
}

Answer 8

Check here there is example code exactly for that: http://developer.android.com/guide/topics/ui/layout/listview.html