Connecting slots and signals in PyQt4 in a loop

问题

Im trying to build a calculator with PyQt4 and connecting the \'clicked()\' signals from the buttons doesn\'t work as expected. Im creating my buttons for the numbers inside a for loop where i try to connect them afterwards.

def __init__(self):
    for i in range(0,10):
        self._numberButtons += [QPushButton(str(i), self)]
        self.connect(self._numberButtons[i], SIGNAL(\'clicked()\'), lambda : self._number(i))

def _number(self, x):
    print(x)

When I click on the buttons all of them print out \'9\'. Why is that so and how can i fix this?

回答1:

This is just, how scoping, name lookup and closures are defined in Python.

Python only introduces new bindings in namespace through assignment and through parameter lists of functions. i is therefore not actually defined in the namespace of the lambda, but in the namespace of __init__(). The name lookup for i in the lambda consequently ends up in the namespace of __init__(), where i is eventually bound to 9. This is called "closure".

You can work around these admittedly not really intuitive (but well-defined) semantics by passing i as a keyword argument with default value. As said, names in parameter lists introduce new bindings in the local namespace, so i inside the lambda then becomes independent from i in .__init__():

self._numberButtons[i].clicked.connect(lambda i=i: self._number(i))

A more readable, less magic alternative is functools.partial:

self._numberButtons[i].clicked.connect(partial(self._number, i))

I'm using new-style signal and slot syntax here simply for convenience, old style syntax works just the same.

回答2:

You are creating closures. Closures really capture a variable, not the value of a variable. At the end of __init__, i is the last element of range(0, 10), i.e. 9. All the lambdas you created in this scope refer to this i and only when they are invoked, they get the value of i at the time they are at invoked (however, seperate invocations of __init__ create lambdas referring to seperate variables!).

There are two popular ways to avoid this:

1. Using a default parameter: lambda i=i: self._number(i). This work because default parameters bind a value at function definition time.
2. Defining a helper function helper = lambda i: (lambda: self._number(i)) and use helper(i) in the loop. This works because the "outer" i is evaluated at the time i is bound, and - as mentioned before - the next closure created in the next invokation of helper will refer to a different variable.

回答3:

Use the Qt way, use QSignalMapper instead.

来源：https://stackoverflow.com/questions/4578861/connecting-slots-and-signals-in-pyqt4-in-a-loop