Python 'in' keyword in expression vs. in for loop [duplicate]

╄→尐↘猪︶ㄣ 提交于 2019-11-29 02:04:06

They are the same concept but not the same operators.

In the print(2 in some_list) example, in is an operator that handles several different situations. The Python docs for the in operator give the details, which I paraphrase as follows: x in y calls y.__contains__(x) if y has a __contains__ member function. Otherwise, x in y tries iterating through y.__iter__() to find x, or calls y.__getitem__(x) if __iter__ doesn't exist. The complexity is to provide consistent membership testing for older code as well as newer code — __contains__ is what you want if you're implementing your own classes.

In the for loop, in is just a marker that separates the loop-index variable from whatever you're looping over. The Python docs for the for loop discuss the semantics, which I paraphrase as follows: whatever comes after in is evaluated at the beginning of a loop to provide an iterator. The loop body then runs for each element of the iterator (barring break or other control-flow changes). The for statement doesn't worry about __contains__ or __getitem__.

Edit @Kelvin makes a good point: you can change the behaviour of in with respect to your own new-style classes (class foo(object)):

No, it is not the same. The in test like in your first example is a test for membership and returns a truth value. This in might be thought of as the sequential analogue of == or is (depending on how __contains__ is implemented).

The in in your second example is part of the iteration grammar; it temporarily binds your selected variable i to each item in the iterable. This in might be thought of as the sequential analogue of =, the assignment operator.

No, although they both use the same word they do different things. in is in both cases a syntax structure, e.g. it is not a name of a object and can't be changed. You can see here and here the syntactic definition of each one. As you can see the names are hardcoded and have no relationship.

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