How to use JPA Criteria API when joining many tables

时光毁灭记忆、已成空白 提交于 2019-11-28 23:39:05

If you use canonical Metamodel, you'll avoid this kind of errors. In your code you have misused the "dentist" keyword, that's probably the cause of your error, because "dentist" is not a field in Company entity.

However, looking at how you defined your class in the other question, the way to define that join using Metamodel is this:

SetJoin<Company,Product> products = companyRoot.join(Company_.products); 

As you can see, Metamodel avoids the use of strings, and so avoids a lot of runtime errors. If anyway you don't use Metamodel, try this:

SetJoin<Company,Product> products = companyRoot.join("products"); 

If you now want to add a predicate, i.e. something after the where, you'll write something like:

Predicate predicate = criteriaBuilder.equal(products.get(Product_.category), "dentist");
criteria.where(predicate);

If you want to add a join for the City entity:

Join<Company, City> city = companyRoot.join(Company_.city);
predicate = criteriaBuilder.and(predicate, criteriaBuilder.equal(city.get(City_.cityName), "Leeds");
criteria.where(predicate);

(supposing that the field cityName is the correct field name for your city).

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