How to set constraints on generic types in Java?

Question

I have a generic class:

public class ListObject<T>
{
    // fields
    protected T _Value = null;
      // ..
}

Now I want to do something like the following:

ListObject<MyClass> foo = new ListObject<MyClass>();
ListObject<MyClass> foo2 = new ListObject<MyClass>();
foo.compareTo(foo2);

Question:

How can I define the compareTo() method with resprect to the generic T?

I guess I have to somehow implement a constraint on the generic T, to tell that T implements a specific interface (maybe Comparable, if that one exists).

Can anyone provide me with a small code sample?

Answer 1

Read also the discussion here: Generics and sorting in Java

Short answer, the best you can get is:

class ListObject<T extends Comparable<? super T>> {
    ...
}

But there is also reason to just use:

class ListObject<T extends Comparable> {
    ...
}

Answer 2

This depends on exactly what you want the compareTo method to do. Simply defining the compareTo method to take other ListObject<T> values is done by the following

public class ListObject<T> {
  public int compareTo(ListObject<T> other) {
    ...
  }
}

However if you want to actually call methods on that parameter you'll need to add some constraints to give more information about the T value like so

class ListObject<T extends Comparable<T>> {
  ...
}

Answer 3

Try public class ListObject<T extends U>. Only Ts which implement U (or derive from U) will be allowable substitutions.

Answer 4

public class ListObject<T implements Comparable> {...}