How to get HttpClient returning status code and response body?

怎甘沉沦 提交于 2019-11-28 22:22:24

Don't provide the handler to execute.

Get the HttpResponse object, use the handler to get the body and get the status code from it directly

HttpResponse response = client.execute(httpGet);
String body = handler.handleResponse(response);
int code = response.getStatusLine().getStatusCode();

You can avoid the BasicResponseHandler, but use the HttpResponse itself to get both status and response as a String.

HttpResponse response = httpClient.execute(get);

// Getting the status code.
int statusCode = response.getStatusLine().getStatusCode();

// Getting the response body.
String responseBody = EntityUtils.toString(response.getEntity());

BasicResponseHandler throws if the status is not 2xx. See its javadoc.

Here is how I would do it:

HttpResponse response = client.execute( get );
int code = response.getStatusLine().getStatusCode();
InputStream body = response.getEntity().getContent();
// Read the body stream

Or you can also write a ResponseHandler starting from BasicResponseHandler source that don't throw when the status is not 2xx.

Fluent facade API:

Response response = Request.Get(uri)
        .connectTimeout(MILLIS_ONE_SECOND)
        .socketTimeout(MILLIS_ONE_SECOND)
        .execute();
HttpResponse httpResponse = response.returnResponse();
StatusLine statusLine = httpResponse.getStatusLine();
if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
    // 响应内容编码自适应?(好像没那么智能)
    String responseContent = EntityUtils.toString(
            httpResponse.getEntity(), StandardCharsets.UTF_8.name());
}

If you are using Spring

        return  new ResponseEntity<String>("your response", HttpStatus.ACCEPTED);
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