Say I have a binary file; it contains positive binary numbers, but written in little endian as 32-bit integers
How do I read this file? I have this right now.
int main() {
FILE * fp;
char buffer[4];
int num = 0;
fp=fopen("file.txt","rb");
while ( fread(&buffer, 1, 4,fp) != 0) {
// I think buffer should be 32 bit integer I read,
// how can I let num equal to 32 bit little endian integer?
}
// Say I just want to get the sum of all these binary little endian integers,
// is there an another way to make read and get sum faster since it's all
// binary, shouldnt it be faster if i just add in binary? not sure..
return 0;
}
Vaughn Cato
This is one way to do it that works on either big-endian or little-endian architectures:
int main() {
unsigned char bytes[4];
int sum = 0;
FILE *fp=fopen("file.txt","rb");
while ( fread(bytes, 4, 1,fp) != 0) {
sum += bytes[0] | (bytes[1]<<8) | (bytes[2]<<16) | (bytes[3]<<24);
}
return 0;
}
If you are using linux you should look here ;-)
It is about useful functions such as le32toh
From CodeGuru:
inline void endian_swap(unsigned int& x)
{
x = (x>>24) |
((x<<8) & 0x00FF0000) |
((x>>8) & 0x0000FF00) |
(x<<24);
}
So, you can read directly to unsigned int
and then just call this.
while ( fread(&num, 1, 4,fp) != 0) {
endian_swap(num);
// conversion done; then use num
}
来源:https://stackoverflow.com/questions/13001183/how-to-read-little-endian-integers-from-file-in-c