PAT A1028 List Sorting

限于喜欢 提交于 2019-11-28 20:10:52

PAT A1028 List Sorting

题目描述:

  Excel can sort records according to any column. Now you are supposed to imitate this function.

  Input Specification:
  Each input file contains one test case. For each case, the first line contains two integers N (≤10​5​​) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

  Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

  Sample Input 1:
  3 1
  000007 James 85
  000010 Amy 90
  000001 Zoe 60

  Sample Output 1:
  000001 Zoe 60
  000007 James 85
  000010 Amy 90

  Sample Input 2:
  4 2
  000007 James 85
  000010 Amy 90
  000001 Zoe 60
  000002 James 98

  Sample Output 2:
  000010 Amy 90
  000002 James 98
  000007 James 85
  000001 Zoe 60

  Sample Input 3:
  4 3
  000007 James 85
  000010 Amy 90
  000001 Zoe 60
  000002 James 90

  Sample Output 3:
  000001 Zoe 60
  000007 James 85
  000002 James 90
  000010 Amy 90

参考代码:

 1 /**************************************************
 2 PAT A1028 List Sorting
 3 **************************************************/
 4 #include <iostream>
 5 #include <algorithm>
 6 #include <vector>
 7 
 8 using namespace std;
 9 
10 struct StuRecord {
11     string id;
12     string name;
13     int grade = 0;
14 };
15 
16 //自定义比较函数
17 bool cmpById(StuRecord a, StuRecord b) { return  a.id < b.id; }
18 bool cmpByName(StuRecord a, StuRecord b) { return a.name == b.name ? a.id < b.id : a.name < b.name; }
19 bool cmpByGrade(StuRecord a, StuRecord b) { return a.grade == b.grade ? a.id < b.id : a.grade < b.grade; }
20 bool(*cmp[3])(StuRecord, StuRecord) = { cmpById, cmpByName, cmpByGrade };
21 
22 int main() {
23     vector<StuRecord> recordList;
24     int recordCnt = 0, compareFunc = 0;
25 
26     cin >> recordCnt >> compareFunc;
27 
28     //读入记录
29     StuRecord temp;
30     for (int i = 0; i < recordCnt; ++i) {
31         cin >> temp.id >> temp.name >> temp.grade;
32         recordList.push_back(temp);
33     }
34 
35     //按照指定方式进行排列
36     sort(recordList.begin(), recordList.end(), cmp[compareFunc - 1]);
37 
38     //输出排列结果
39     for (int i = 0; i < recordList.size(); ++i) {
40         cout << recordList[i].id << ' ' << recordList[i].name << ' ' << recordList[i].grade;
41         if (i != recordList.size() - 1) cout << endl;
42     }
43 
44     return 0;
45 }

注意事项:

  1:递增顺寻排列和非递减顺序排列实质上是一样的。

  2:注意函数指针的使用;指针相关的操作见下文(待补充):

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