Dojo and unregistering widgets

淺唱寂寞╮ 提交于 2019-11-28 19:13:13
Jez

If you're looking to unregister specific widgets, you can use their destroy() or destroyRecursive() methods. The second one destroys any widgets inside the one you are destroying (i.e. calling destroyRecursive on a form widget will also destroy all the form components).

In your case, it sounds like your best bet would be to do this before jQuery.load -

var widgets = dijit.findWidgets(<containerDiv>);
dojo.forEach(widgets, function(w) {
    w.destroyRecursive(true);
});

The above code will unregister all widgets in <containerDiv>, and preserve their associated DOM Nodes. To destroy the DOM nodes, pass false to destroyRecursive instead.

Reference:

http://dojotoolkit.org/api/1.3/dijit/_Widget/destroyRecursive

Based on http://bugs.dojotoolkit.org/ticket/5438, I found a sufficient way of destroying dojo-widgets:

dijit.registry.forEach(function(w){
                  w.destroy();             
          });
Kds

This worked for me:

dijit.byId( 'myButton' ).destroy( true );

I think you would be better off removing the id from your button and accessing it using an attach point. You would basically do <button dojoType="dijit.form.Button" data-dojo-attach-point="myButton">button</button>

then in your code you would access it like this.myButton.... however im not sure which version of dojo you are using. This will fix any id issues since dojo will assign a unique id to it automatically.

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