I have to convert docx file format (which is in openXML format) into JSON format. I need some guidelines to do it. Thanks in advance.
You may take a look at the Json-lib Java library, that provides XML-to-JSON conversion.
String xml = "<hello><test>1.2</test><test2>123</test2></hello>";
XMLSerializer xmlSerializer = new XMLSerializer();
JSON json = xmlSerializer.read( xml );
If you need the root tag too, simply add an outer dummy tag:
String xml = "<hello><test>1.2</test><test2>123</test2></hello>";
XMLSerializer xmlSerializer = new XMLSerializer();
JSON json = xmlSerializer.read("<x>" + xml + "</x>");
There is no direct mapping between XML and JSON; XML carries with it type information (each element has a name) as well as namespacing. Therefore, unless each JSON object has type information embedded, the conversion is going to be lossy.
But that doesn't necessarily matter. What does matter is that the consumer of the JSON knows the data contract. For example, given this XML:
<books>
<book author="Jimbo Jones" title="Bar Baz">
<summary>Foo</summary>
</book>
<book title="Don't Care" author="Fake Person">
<summary>Dummy Data</summary>
</book>
</books>
You could convert it to this:
{
"books": [
{ "author": "Jimbo Jones", "title": "Bar Baz", "summary": "Foo" },
{ "author": "Fake Person", "title": "Don't Care", "summary": "Dummy Data" },
]
}
And the consumer wouldn't need to know that each object in the books collection was a book object.
Edit:
If you have an XML Schema for the XML and are using .NET, you can generate classes from the schema using xsd.exe. Then, you could parse the source XML into objects of these classes, then use a DataContractJsonSerializer to serialize the classes as JSON.
If you don't have a schema, it will be hard getting around manually defining your JSON format yourself.
The XML class in the org.json namespace provides you with this functionality.
You have to call the static toJSONObject method
Converts a well-formed (but not necessarily valid) XML string into a JSONObject. Some information may be lost in this transformation because JSON is a data format and XML is a document format. XML uses elements, attributes, and content text, while JSON uses unordered collections of name/value pairs and arrays of values. JSON does not does not like to distinguish between elements and attributes. Sequences of similar elements are represented as JSONArrays. Content text may be placed in a "content" member. Comments, prologs, DTDs, and <[ [ ]]> are ignored.
If you are dissatisfied with the various implementations, try rolling your own. Here is some code I wrote this afternoon to get you started. It works with net.sf.json and apache common-lang:
static public JSONObject readToJSON(InputStream stream) throws Exception {
SAXParserFactory factory = SAXParserFactory.newInstance();
factory.setNamespaceAware(true);
SAXParser parser = factory.newSAXParser();
SAXJsonParser handler = new SAXJsonParser();
parser.parse(stream, handler);
return handler.getJson();
}
And the SAXJsonParser implementation:
package xml2json;
import net.sf.json.*;
import org.apache.commons.lang.StringUtils;
import org.xml.sax.*;
import org.xml.sax.helpers.DefaultHandler;
import java.util.ArrayList;
import java.util.List;
public class SAXJsonParser extends DefaultHandler {
static final String TEXTKEY = "_text";
JSONObject result;
List<JSONObject> stack;
public SAXJsonParser(){}
public JSONObject getJson(){return result;}
public String attributeName(String name){return "@"+name;}
public void startDocument () throws SAXException {
stack = new ArrayList<JSONObject>();
stack.add(0,new JSONObject());
}
public void endDocument () throws SAXException {result = stack.remove(0);}
public void startElement (String uri, String localName,String qName, Attributes attributes) throws SAXException {
JSONObject work = new JSONObject();
for (int ix=0;ix<attributes.getLength();ix++)
work.put( attributeName( attributes.getLocalName(ix) ), attributes.getValue(ix) );
stack.add(0,work);
}
public void endElement (String uri, String localName, String qName) throws SAXException {
JSONObject pop = stack.remove(0); // examine stack
Object stashable = pop;
if (pop.containsKey(TEXTKEY)) {
String value = pop.getString(TEXTKEY).trim();
if (pop.keySet().size()==1) stashable = value; // single value
else if (StringUtils.isBlank(value)) pop.remove(TEXTKEY);
}
JSONObject parent = stack.get(0);
if (!parent.containsKey(localName)) { // add new object
parent.put( localName, stashable );
}
else { // aggregate into arrays
Object work = parent.get(localName);
if (work instanceof JSONArray) {
((JSONArray)work).add(stashable);
}
else {
parent.put(localName,new JSONArray());
parent.getJSONArray(localName).add(work);
parent.getJSONArray(localName).add(stashable);
}
}
}
public void characters (char ch[], int start, int length) throws SAXException {
JSONObject work = stack.get(0); // aggregate characters
String value = (work.containsKey(TEXTKEY) ? work.getString(TEXTKEY) : "" );
work.put(TEXTKEY, value+new String(ch,start,length) );
}
public void warning (SAXParseException e) throws SAXException {
System.out.println("warning e=" + e.getMessage());
}
public void error (SAXParseException e) throws SAXException {
System.err.println("error e=" + e.getMessage());
}
public void fatalError (SAXParseException e) throws SAXException {
System.err.println("fatalError e=" + e.getMessage());
throw e;
}
}
If you need to be able to manipulate your XML before it gets converted to JSON, or want fine-grained control of your representation, go with XStream. It's really easy to convert between: xml-to-object, json-to-object, object-to-xml, and object-to-json. Here's an example from XStream's docs:
XML:
<person>
<firstname>Joe</firstname>
<lastname>Walnes</lastname>
<phone>
<code>123</code>
<number>1234-456</number>
</phone>
<fax>
<code>123</code>
<number>9999-999</number>
</fax>
</person>
POJO (DTO):
public class Person {
private String firstname;
private String lastname;
private PhoneNumber phone;
private PhoneNumber fax;
// ... constructors and methods
}
Convert from XML to POJO:
String xml = "<person>...</person>";
XStream xstream = new XStream();
Person person = (Person)xstream.fromXML(xml);
And then from POJO to JSON:
XStream xstream = new XStream(new JettisonMappedXmlDriver());
String json = xstream.toXML(person);
Note: although the method reads toXML() XStream will produce JSON, since the Jettison driver is used.
Converting complete docx files into JSON does not look like a good idea, because docx is a document centric XML format and JSON is a data centric format. XML in general is designed to be both, document and data centric. Though it is technical possible to convert document centric XML into JSON, handling the generated data might be overly complex. Try to focus on the actual needed data and convert only that part.
If you have a valid dtd file for the xml snippet, then you can easily convert xml to json and json to xml using the open source eclipse link jar. Detailed sample JAVA project can be found here: http://www.cubicrace.com/2015/06/How-to-convert-XML-to-JSON-format.html
I have come across a tutorial, hope it helps you. http://www.techrecite.com/xml-to-json-data-parser-converter
Docx4j
I've used docx4j before, and it's worth taking a look at.
unXml
You could also check out my open source unXml-library that is available on Maven Central.
It is lightweight, and has a simple syntax to pick out XPaths from your xml, and get them returned as Json attributes in a Jackson ObjectNode.
Use xmlSerializer.setForceTopLevelObject(true) to include root element in resulting JSON.
Your code would be like this
String xml = "<hello><test>1.2</test><test2>123</test2></hello>";
XMLSerializer xmlSerializer = new XMLSerializer();
xmlSerializer.setForceTopLevelObject(true);
JSON json = xmlSerializer.read(xml);
来源：https://stackoverflow.com/questions/5113711/convert-xml-to-json-format