How to create a unique slug in Django

I am trying to create a unique slug in Django so that I can access a post via a url like this: http://www.example.com/buy-a-new-bike_Boston-MA-02111_2

The relevant models:

class ZipCode(models.Model):
    zipcode = models.CharField(max_length=5)
    city = models.CharField(max_length=64)
    statecode = models.CharField(max_length=32)

class Need(models.Model):
    title = models.CharField(max_length=50)
    us_zip = models.CharField(max_length=5)
    slug = ?????

    def get_city():
        zip = ZipCode.objects.get(zipcode=self.us_zip)
        city = "%s, %s %s" % (zip.city, zip.statecode, zip.zipcode)
        return city

A sample ZipCode record:

zipcode = "02111"
city = "Boston"
statecode = "MA"

A sample Need record:

title = "buy a new bike"
us_zip = "02111"
slug = "buy-a-new-bike_Boston-MA-02111_2" (desired)

Any tips as to how to create this unique slug? Its composition is:

Need.title + "_" + Need.get_city() + "_" + an optional incrementing integer to make it unique. All spaces should be replaced with "-".

NOTE: My desired slug above assumes that the slug "buy-a-new-bike_Boston-MA-02111" already exists, which is what it has the "_2" appended to it to make it unique.

I've tried django-extensions, but it seems that it can only take a field or tuple of fields to construct the unique slug. I need to pass in the get_city() function as well as the "_" connector between the title and city. Anyone solved this and willing to share?

Thank you!

UPDATE

I'm already using django-extensions for its UUIDField, so it would be nice if it could also be usable for its AutoSlugField!

Srikanth Chundi

I use this snippet for generating unique slug and my typical save method look like below

slug will be Django SlugField with blank=True but enforce slug in save method.

typical save method for Need model might look below

def save(self, **kwargs):
    slug_str = "%s %s" % (self.title, self.us_zip) 
    unique_slugify(self, slug_str) 
    super(Need, self).save(**kwargs)

and this will generate slug like buy-a-new-bike_Boston-MA-02111 , buy-a-new-bike_Boston-MA-02111-1 and so on. Output might be little different but you can always go through snippet and customize to your needs.

My little code:

def save(self, *args, **kwargs):
    strtime = "".join(str(time()).split("."))
    string = "%s-%s" % (strtime[7:], self.title)
    self.slug = slugify(string)
    super(Need, self).save()

If you are thinking of using an app to do it for you, here is one.

https://github.com/un33k/django-uuslug

UUSlug = (``U``nique + ``U``code Slug)


Unicode Test Example
=====================
from uuslug import uuslug as slugify

s = "This is a test ---"
r = slugify(s)
self.assertEquals(r, "this-is-a-test")

s = 'C\'est déjà l\'été.'
r = slugify(s)
self.assertEquals(r, "c-est-deja-l-ete")

s = 'Nín hǎo. Wǒ shì zhōng guó rén'
r = slugify(s)
self.assertEquals(r, "nin-hao-wo-shi-zhong-guo-ren")

s = '影師嗎'
r = slugify(s)
self.assertEquals(r, "ying-shi-ma")


Uniqueness Test Example
=======================
Override your objects save method with something like this (models.py)

from django.db import models
from uuslug import uuslug as slugify

class CoolSlug(models.Model):
    name = models.CharField(max_length=100)
    slug = models.CharField(max_length=200)

    def __unicode__(self):
        return self.name

    def save(self, *args, **kwargs):
        self.slug = slugify(self.name, instance=self)
        super(CoolSlug, self).save(*args, **kwargs)

Test:
=====

name = "john"
c = CoolSlug.objects.create(name=name)
c.save()
self.assertEquals(c.slug, name) # slug = "john"

c1 = CoolSlug.objects.create(name=name)
c1.save()
self.assertEquals(c1.slug, name+"-1") # slug = "john-1"

This is a simple implementation that generate the slug from the title, it doesn't depend on other snippets:

from django.template.defaultfilters import slugify

class Article(models.Model):
    ...
    def save(self, **kwargs):
        if not self.slug:
            slug = slugify(self.title)
            while True:
                try:
                    article = Article.objects.get(slug=slug)
                    if article == self:
                        self.slug = slug
                        break
                    else:
                        slug = slug + '-'
                except:
                    self.slug = slug
                    break

        super(Article, self).save()

frostcs

Django provides a SlugField model field to make this easier for you. Here's an example of it in a "blog" app's

class Post(models.Model):
    title = models.CharField(max_length=100)
    content = models.TextField(blank=True)

    slug = models.SlugField(unique=True)

    @models.permalink
    def get_absolute_url(self):
        return 'blog:post', (self.slug,)

Note that we've set unique=True for our slug field — in this project we will be looking up posts by their slug, so we need to ensure they are unique. Here's what our application's views.py might look like to do this:

from .models import Post

def post(request, slug):
    post = get_object_or_404(Post, slug=slug)

    return render(request, 'blog/post.html', {
        'post': post,
    })

Hi can you tried this function

class Training(models.Model):
    title = models.CharField(max_length=250)
    text = models.TextField()
    created_date = models.DateTimeField(
    auto_now_add=True, editable=False, )
    slug = models.SlugField(unique=True, editable=False, max_length=250)

    def __unicode__(self):
       return self.title

    def save(self, *args, **kwargs):
       self.slug =get_unique_slug(self.id,self.title,Training.objects)
       return super(Training, self).save(*args, **kwargs)

def get_unique_slug(id,title,obj):
    slug = slugify(title.replace('ı', 'i'))
    unique_slug = slug
    counter = 1
    while obj.filter(slug=unique_slug).exists():
       if(obj.filter(slug=unique_slug).values('id')[0]['id']==id):
           break
       unique_slug = '{}-{}'.format(slug, counter)
       counter += 1
    return unique_slug

Try this, worked out for me,welcome in advance:

class Parcel(models.Model):
    title = models.CharField(max_length-255)
    slug = models.SlugField(unique=True, max_length=255)
    weight = models.IntegerField()
    description = models.CharField(max_length=255)
    destination = models.CharField(max_length=255)
    origin = models.CharField(max_length=255)

    def __str__(self):
        return self.description

    def save(self, *args, **kwargs):
        if not self.slug:
            t_slug = slugify(self.title)
            startpoint = 1
            unique_slug = t_slug
            while Parcel.objects.filter(slug=unique_slug).exists():
                unique_slug = '{} {}'.format(t_slug, origin)
                origin += 1
            self.slug = unique_slug
        super().save(*args, **kwargs)

qingfeng

class Need(models.Model):
    title = models.CharField(max_length=50)
    us_zip = models.CharField(max_length=5)
    slug = models.SlugField(unique=True)

    def save(self, **kwargs):
        slug_str = "%s %s" % (self.title, self.us_zip) 
        super(Need, self).save()

来源：https://stackoverflow.com/questions/3816307/how-to-create-a-unique-slug-in-django

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django

django-models

slug