Java BigDecimal: Round to the nearest whole value

问题

I need the following results

100.12 -> 100.00
100.44 -> 100.00
100.50 -> 101.00
100.75 -> 101.00

.round() or .setScale() ? How do I go about this?

回答1:

You can use setScale() to reduce the number of fractional digits to zero. Assuming value holds the value to be rounded:

BigDecimal scaled = value.setScale(0, RoundingMode.HALF_UP);
System.out.println(value + " -> " + scaled);

Using round() is a bit more involved as it requires you to specify the number of digits to be retained. In your examples this would be 3, but this is not valid for all values:

BigDecimal rounded = value.round(new MathContext(3, RoundingMode.HALF_UP));
System.out.println(value + " -> " + rounded);

(Note that BigDecimal objects are immutable; both setScale and round will return a new object.)

回答2:

If i go by Grodriguez's answer

System.out.println("" + value);
value = value.setScale(0, BigDecimal.ROUND_HALF_UP);
System.out.println("" + value);

This is the output

100.23 -> 100
100.77 -> 101

Which isn't quite what i want, so i ended up doing this..

System.out.println("" + value);
value = value.setScale(0, BigDecimal.ROUND_HALF_UP);
value = value.setScale(2, BigDecimal.ROUND_HALF_UP);
System.out.println("" + value);

This is what i get

100.23 -> 100.00
100.77 -> 101.00

This solves my problem for now .. : ) Thank you all.

回答3:

Here's an awfully complicated solution, but it works:

public static BigDecimal roundBigDecimal(final BigDecimal input){
    return input.round(
        new MathContext(
            input.toBigInteger().toString().length(),
            RoundingMode.HALF_UP
        )
    );
}

Test Code:

List<BigDecimal> bigDecimals =
    Arrays.asList(new BigDecimal("100.12"),
        new BigDecimal("100.44"),
        new BigDecimal("100.50"),
        new BigDecimal("100.75"));
for(final BigDecimal bd : bigDecimals){
    System.out.println(roundBigDecimal(bd).toPlainString());
}

Output:

100
100
101
101

回答4:

Simply look at:

http://download.oracle.com/javase/6/docs/api/java/math/BigDecimal.html#ROUND_HALF_UP

and:

setScale(int precision, int roundingMode)

Or if using Java 6, then

http://download.oracle.com/javase/6/docs/api/java/math/RoundingMode.html#HALF_UP

http://download.oracle.com/javase/6/docs/api/java/math/MathContext.html

and either:

setScale(int precision, RoundingMode mode);
round(MathContext mc);

回答5:

I don't think you can round it like that in a single command. Try

    ArrayList<BigDecimal> list = new ArrayList<BigDecimal>();
    list.add(new BigDecimal("100.12"));
    list.add(new BigDecimal("100.44"));
    list.add(new BigDecimal("100.50"));
    list.add(new BigDecimal("100.75"));

    for (BigDecimal bd : list){
        System.out.println(bd+" -> "+bd.setScale(0,RoundingMode.HALF_UP).setScale(2));
    }

Output:
100.12 -> 100.00
100.44 -> 100.00
100.50 -> 101.00
100.75 -> 101.00

I tested for the rest of your examples and it returns the wanted values, but I don't guarantee its correctness.

回答6:

You want

round(new MathContext(0));  // or perhaps another math context with rounding mode HALF_UP

来源：https://stackoverflow.com/questions/4134047/java-bigdecimal-round-to-the-nearest-whole-value

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java

rounding

bigdecimal