Load Lua-files by relative path

问题

If I have a file structure like this:

./main.lua
./mylib/mylib.lua
./mylib/mylib-utils.lua
./mylib/mylib-helpers.lua
./mylib/mylib-other-stuff.lua

From main.lua the file mylib.lua can be loaded with full path require('mylib.mylib'). But inside mylib.lua I would also like to load other necessary modules and I don't feel like always specifying the full path (e.g. mylib.mylib-utils). If I ever decide to move the folder I'm going to have a lot of search and replace. Is there a way to use just the relative part of the path?

UPD. I'm using Lua with Corona SDK, if that matters.

回答1:

There is a way of deducing the "local path" of a file (more concretely, the string that was used to load the file).

If you are requiring a file inside lib.foo.bar, you might be doing something like this:

require 'lib.foo.bar'

Then you can get the path to the file as the first element (and only) ... variable, when you are outside all functions. In other words:

-- lib/foo/bar.lua
local pathOfThisFile = ... -- pathOfThisFile is now 'lib.foo.bar'

Now, to get the "folder" you need to remove the filename. Simplest way is using match:

local folderOfThisFile = (...):match("(.-)[^%.]+$") -- returns 'lib.foo.'

And there you have it. Now you can prepend that string to other file names and use that to require:

require(folderOfThisFile .. 'baz')     -- require('lib.foo.baz')
require(folderOfThisFile .. 'bazinga') -- require('lib.foo.bazinga')

If you move bar.lua around, folderOfThisFile will get automatically updated.

回答2:

You can do

package.path = './mylib/?.lua;' .. package.path

local oldreq = require
local require = function(s) return oldreq('mylib.' .. s) end

Then

-- do all the requires
require('mylib-utils')
require('mylib-helpers')
require('mylib-other-stuff')

-- and optionally restore the old require, if you did it the second way
require = oldreq

回答3:

Under the Conky's Lua environment I've managed to include my common.lua (in the same directory) as require(".common"). Note the leading dot . character.

回答4:

I'm using the following snippet. It should work both for files loaded with require, and for files called via the command line. Then use requireRel instead of require for those you wish to be loaded with a relative path.

local requireRel
if arg and arg[0] then
    package.path = arg[0]:match("(.-)[^\\/]+$") .. "?.lua;" .. package.path
    requireRel = require
elseif ... then
    local d = (...):match("(.-)[^%.]+$")
    function requireRel(module) return require(d .. module) end
end

来源：https://stackoverflow.com/questions/9145432/load-lua-files-by-relative-path

标签

lua

require

corona