问题
Is it possible to integrate Spring managed Hibernate interceptors (http://docs.jboss.org/hibernate/orm/4.3/manual/en-US/html/ch14.html) in Spring Boot?
I\'m using Spring Data JPA and Spring Data REST and need an Hibernate interceptor to act on an update of a particular field on an entity.
With standard JPA events it\'s not possible to get the old values, and hence I think I need to use the Hibernate interceptor.
回答1:
There's not a particularly easy way to add a Hibernate interceptor that is also a Spring Bean but you can easily add an interceptor if it's manged entirely by Hibernate. To do that add the following to your application.properties:
spring.jpa.properties.hibernate.ejb.interceptor=my.package.MyInterceptorClassName
If you need the Interceptor to also be a bean you can create your own LocalContainerEntityManagerFactoryBean. The EntityManagerFactoryBuilder from Spring Boot 1.1.4 is a little too restrictive with the generic of the properties so you need cast to (Map), we'll look at fixing that for 1.2.
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory(
EntityManagerFactoryBuilder factory, DataSource dataSource,
JpaProperties properties) {
Map<String, Object> jpaProperties = new HashMap<String, Object>();
jpaProperties.putAll(properties.getHibernateProperties(dataSource));
jpaProperties.put("hibernate.ejb.interceptor", hibernateInterceptor());
return factory.dataSource(dataSource).packages("sample.data.jpa")
.properties((Map) jpaProperties).build();
}
@Bean
public EmptyInterceptor hibernateInterceptor() {
return new EmptyInterceptor() {
@Override
public boolean onLoad(Object entity, Serializable id, Object[] state,
String[] propertyNames, Type[] types) {
System.out.println("Loaded " + id);
return false;
}
};
}
回答2:
Taking the several threads as reference I ended up with the following solution:
I am using Spring-Boot 1.2.3.RELEASE (which is the current ga at the moment)
My use case was that described in this bug (DATAREST-373).
I needed to be able to encode the password of a User @Entity upon create, and have special logic upon save. The create was very straightforward using @HandleBeforeCreate and checking the @Entity id for 0L equality.
For the save I implemented a Hibernate Interceptor which extends an EmptyInterceptor
@Component
class UserInterceptor extends EmptyInterceptor{
@Autowired
PasswordEncoder passwordEncoder;
@Override
boolean onFlushDirty(Object entity, Serializable id, Object[] currentState, Object[] previousState, String[] propertyNames, Type[] types) {
if(!(entity instanceof User)){
return false;
}
def passwordIndex = propertyNames.findIndexOf { it == "password"};
if(entity.password == null && previousState[passwordIndex] !=null){
currentState[passwordIndex] = previousState[passwordIndex];
}else{
currentState[passwordIndex] = passwordEncoder.encode(currentState[passwordIndex]);
}
return true;
}
}
Using spring boot the documentation states that
all properties in spring.jpa.properties.* are passed through as normal JPA properties (with the prefix stripped) when the local EntityManagerFactory is created.
As many references stated, we can defined our interceptor using spring.jpa.properties.hibernate.ejb.interceptor in our Spring-Boot configuration. However I couldn't get the @Autowire PasswordEncoder to work.
So I resorted to using HibernateJpaAutoConfiguration and overriding protected void customizeVendorProperties(Map<String, Object> vendorProperties). Here is my configuration.
@Configuration
public class HibernateConfiguration extends HibernateJpaAutoConfiguration{
@Autowired
Interceptor userInterceptor;
@Override
protected void customizeVendorProperties(Map<String, Object> vendorProperties) {
vendorProperties.put("hibernate.ejb.interceptor",userInterceptor);
}
}
Autowiring the Interceptor instead of allowing Hibernate to instantiate it was the key to getting it to work.
What bothers me now is that the logic is split in two, but hopefully once DATAREST-373 is resolved then this wont be necessary.
回答3:
My simple one file example of hibernate listeners for spring boot (spring-boot-starter 1.2.4.RELEASE)
import org.hibernate.event.service.spi.EventListenerRegistry;
import org.hibernate.event.spi.*;
import org.hibernate.internal.SessionFactoryImpl;
import org.hibernate.jpa.HibernateEntityManagerFactory;
import org.springframework.stereotype.Component;
import org.springframework.web.context.request.RequestAttributes;
import org.springframework.web.context.request.RequestContextHolder;
import javax.annotation.PostConstruct;
import javax.inject.Inject;
import javax.persistence.EntityManagerFactory;
@Component
public class UiDateListener implements PostLoadEventListener, PreUpdateEventListener {
@Inject EntityManagerFactory entityManagerFactory;
@PostConstruct
private void init() {
HibernateEntityManagerFactory hibernateEntityManagerFactory = (HibernateEntityManagerFactory) this.entityManagerFactory;
SessionFactoryImpl sessionFactoryImpl = (SessionFactoryImpl) hibernateEntityManagerFactory.getSessionFactory();
EventListenerRegistry registry = sessionFactoryImpl.getServiceRegistry().getService(EventListenerRegistry.class);
registry.appendListeners(EventType.POST_LOAD, this);
registry.appendListeners(EventType.PRE_UPDATE, this);
}
@Override
public void onPostLoad(PostLoadEvent event) {
final Object entity = event.getEntity();
if (entity == null) return;
// some logic after entity loaded
}
@Override
public boolean onPreUpdate(PreUpdateEvent event) {
final Object entity = event.getEntity();
if (entity == null) return false;
// some logic before entity persist
return false;
}
}
回答4:
Solution using Spring Boot 2
@Component
public class MyInterceptorRegistration implements HibernatePropertiesCustomizer {
@Autowired
private MyInterceptor myInterceptor;
@Override
public void customize(Map<String, Object> hibernateProperties) {
hibernateProperties.put("hibernate.session_factory.interceptor", myInterceptor);
}
}
- I'm using Spring Boot 2.1.7.RELEASE.
- Instead of
hibernate.session_factory.interceptoryou can usehibernate.ejb.interceptor. Both properties work probably because of a backwards compatibility requirement.
Why HibernatePropertiesCustomizer instead of application.properties
One suggested answer is to indicate your interceptor in the spring.jpa.properties.hibernate.ejb.interceptor property in application.properties/yml. This idea may not work if your interceptor is in a lib that will be used by several applications. You want your interceptor to be activated by just adding a dependency to your lib, without requiring each application to alter their application.properties.
回答5:
I had a similar problem with a Spring 4.1.1, Hibernate 4.3.11 application - not Spring Boot.
Solution I found (after reading Hibernate EntityManagerFactoryBuilderImpl code) was that if you pass in a bean reference instead of a class name to hibernate.ejb.interceptor property of the entity manager definition, Hibernate will use that already instantiated bean.
So in my entityManager definition in application context I had something like this:
<bean id="auditInterceptor" class="com.something.AuditInterceptor" />
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
...>
<property name="jpaProperties">
<map>
...
<entry key="hibernate.ejb.interceptor">
<ref bean="auditInterceptor" />
</entry>
...
</map>
</property>
</bean>
The auditInterceptor is managed by Spring, therefore autowiring and other Spring-natured behaviours will be available to it.
回答6:
Hello,
Give this a read: https://github.com/spring-projects/spring-boot/commit/59d5ed58428d8cb6c6d9fb723d0e334fe3e7d9be (use: HibernatePropertiesCustomizer interface)
OR
For simple Interceptor:
In order to configure this in your application you simply need to add: spring.jpa.properties.hibernate.ejb.interceptor = path.to.interceptor (in application.properties). The interceptor itself should be @Component.
As long as the interceptor doesn't actually use any beans. Otherwise it is a bit more complicated but I would be more than happy to offer the solution.
Don't forget to add in application-test.properties, an EmptyInterceptor to not use the logging system (or whatever you want to use it for) in tests (which wouldn't be very helpful).
Hope this was of use to you.
As a final note: always update your Spring / Hibernate versions (use the latest as possible) and you will see that most code will become redundant as newer versions try to reduce the configurations as much as possible.
回答7:
I found another approach after researching two days about how integrate Hibernate Interceptors with Spring Data JPA, my solution is a hybrid between java configuration and xml configuration but this post was very useful. So my final solution was:
AuditLogInterceptor class:
public class AuditLogInterceptor extends EmptyInterceptor{
private int updates;
//interceptor for updates
public boolean onFlushDirty(Object entity,
Serializable id,
Object[] currentState,
Object[] previousState,
String[] propertyNames,
Type[] types) {
if ( entity instanceof Auditable ) {
updates++;
for ( int i=0; i < propertyNames.length; i++ ) {
if ( "lastUpdateTimestamp".equals( propertyNames[i] ) ) {
currentState[i] = new Date();
return true;
}
}
}
return false;
}
}
Datasource Java Configuration:
@Bean
DataSource dataSource() {
//Use JDBC Datasource
DataSource dataSource = new DriverManagerDataSource();
((DriverManagerDataSource)dataSource).setDriverClassName(jdbcDriver);
((DriverManagerDataSource)dataSource).setUrl(jdbcUrl);
((DriverManagerDataSource)dataSource).setUsername(jdbcUsername);
((DriverManagerDataSource)dataSource).setPassword(jdbcPassword);
return dataSource;
}
Entity and Transaction Managers adding the Interceptor
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:persistenceUnitName="InterceptorPersistentUnit" p:persistenceXmlLocation="classpath:audit/persistence.xml"
p:dataSource-ref="dataSource" p:jpaVendorAdapter-ref="jpaAdapter">
<property name="loadTimeWeaver">
<bean class="org.springframework.instrument.classloading.InstrumentationLoadTimeWeaver"/>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
p:entityManagerFactory-ref="entityManagerFactory" />
<bean id="jpaAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"
p:database="ORACLE" p:showSql="true" />
persistence configuration file
<persistence-unit name="InterceptorPersistentUnit">
<class>com.app.CLASSTOINTERCEPT</class>
<shared-cache-mode>ENABLE_SELECTIVE</shared-cache-mode>
<properties>
<property name="hibernate.ejb.interceptor"
value="com.app.audit.AuditLogInterceptor" />
</properties>
</persistence-unit>
回答8:
I ran into this same issue and wound up creating a small spring library to handle all of the setup.
https://github.com/teastman/spring-data-hibernate-event
If you're using Spring Boot, you just add the dependency:
<dependency>
<groupId>io.github.teastman</groupId>
<artifactId>spring-data-hibernate-event</artifactId>
<version>1.0.0</version>
</dependency>
Then add the annotation @HibernateEventListener to any method where the first parameter is the entity you want to listen to, and the second parameter is the Hibernate event that you want to listen for. I've also added the static util function getPropertyIndex to more easily get access to the specific property you want to check, but you can also just look at the raw Hibernate event.
@HibernateEventListener
public void onUpdate(MyEntity entity, PreUpdateEvent event) {
int index = getPropertyIndex(event, "name");
if (event.getOldState()[index] != event.getState()[index]) {
// The name changed.
}
}
回答9:
Because the interceptor do not register as a spring bean，you can use a util which can get ApplicationContext instance,like this:
@Component
public class SpringContextUtil implements ApplicationContextAware {
private static ApplicationContext applicationContext;
@Override
public void setApplicationContext(ApplicationContext applicationContext)
throws BeansException {
SpringContextUtil.applicationContext=applicationContext;
}
public static ApplicationContext getApplicationContext() {
return applicationContext;
}
}
Then you can call the service in the interceptor,like this:
public class SimpleInterceptor extends EmptyInterceptor {
@Override
public String onPrepareStatement(String sql) {
MyService myService=SpringContextUtil.getApplicationContext().getBean(MyService.class);
myService.print();
return super.onPrepareStatement(sql);
}
}
来源：https://stackoverflow.com/questions/25283767/how-to-use-spring-managed-hibernate-interceptors-in-spring-boot