当Repository接口继承了JpaSpecificationExecutor后,我们就可以使用如下接口进行分页查询:
    /**
     * Returns a {@link Page} of entities matching the given {@link Specification}.
     *
     * @param spec can be {@literal null}.
     * @param pageable must not be {@literal null}.
     * @return never {@literal null}.
     */
    Page<T> findAll(@Nullable Specification<T> spec, Pageable pageable);
结合jpa-spec可以很容易构造出Specification:
jpa-spec github地址:https://github.com/wenhao/jpa-spec
public Page<Person> findAll(SearchRequest request) {
    Specification<Person> specification = Specifications.<Person>and()
            .eq(StringUtils.isNotBlank(request.getName()), "name", request.getName())
            .gt(Objects.nonNull(request.getAge()), "age", 18)
            .between("birthday", new Date(), new Date())
            .like("nickName", "%og%", "%me")
            .build();
    return personRepository.findAll(specification, new PageRequest(0, 15));
}
单表查询确实很简单,但对复杂查询,就复杂上些了:
public List<Phone> findAll(SearchRequest request) {
    Specification<Phone> specification = Specifications.<Phone>and()
        .eq(StringUtils.isNotBlank(request.getBrand()), "brand", "HuaWei")
        .eq(StringUtils.isNotBlank(request.getPersonName()), "person.name", "Jack")
        .build();
    return phoneRepository.findAll(specification);
}
这里主表是phone,使用了person的name做条件,使用方法是person.name。
jpa-spec内部会分析person.name,如下代码:
public From getRoot(String property, Root<T> root) {
        if (property.contains(".")) {
            String joinProperty = StringUtils.split(property, ".")[0];
            return root.join(joinProperty, JoinType.LEFT);
        } else {
            return root;
        }
    }
就可看到它用了root.join,那就有一个问题,如果有两个person字段的条件,那就要再join一次,就会生成这样的sql:
select * from phone left outer join person on XX=XX left outer join person XX=XX.
这样肯定不满足需求。这应该也是jpa-spec的一个bug吧
为了解决这个问题,可以使用它提供的另一种方式查询:
public List<Phone> findAll(SearchRequest request) {
    Specification<Person> specification = Specifications.<Person>and()
        .between("age", 10, 35)
        .predicate(StringUtils.isNotBlank(jack.getName()), ((root, query, cb) -> {
            Join address = root.join("addresses", JoinType.LEFT);
            return cb.equal(address.get("street"), "Chengdu");
        }))
        .build();
    return phoneRepository.findAll(specification);
}
这要就可以解决大多数情况了,除了分页
看下正常的单表分页+排序查询:
public Page<Person> findAll(SearchRequest request) {
    Specification<Person> specification = Specifications.<Person>and()
            .eq(StringUtils.isNotBlank(request.getName()), "name", request.getName())
            .gt("age", 18)
            .between("birthday", new Date(), new Date())
            .like("nickName", "%og%")
            .build();
    Sort sort = Sorts.builder()
        .desc(StringUtils.isNotBlank(request.getName()), "name")
        .asc("birthday")
        .build();
    return personRepository.findAll(specification, new PageRequest(0, 15, sort));
}
如果在此基础上增加关联,如下代码:
public Page<Person> findAll(SearchRequest request) {
        Specification<Person> specification = Specifications.<Person>and()
                .predicate(StringUtils.isNotBlank(jack.getName()), ((root, query, cb) -> {
                    Join address = root.join("addresses", JoinType.LEFT);
                    return cb.equal(address.get("street"), "Chengdu");
                }))
                .eq(StringUtils.isNotBlank(request.getName()), "name", request.getName())
                .gt("age", 18)
                .between("birthday", new Date(), new Date())
                .like("nickName", "%og%")
                .build();
        Sort sort = Sorts.builder()
                .desc(StringUtils.isNotBlank(request.getName()), "name")
                .asc("birthday")
                .build();
        return personRepository.findAll(specification, new PageRequest(0, 15, sort));
    }
就会发现addresses的延迟加载失效,生成很多查询addresses的语句,解决方案如下:
public Page<Person> findAll(SearchRequest request) {
        Specification<Person> specification = Specifications.<Person>and()
                .predicate(StringUtils.isNotBlank(jack.getName()), ((root, query, cb) -> {
                    Join address;
                    if (Long.class != query.getResultType()) {
                        address = (Join) root.fetch("addresses", JoinType.LEFT);
                    } else {
                        address = root.join("addresses", JoinType.LEFT);
                    }
                    return cb.equal(address.get("street"), "Chengdu");
                }))
                .eq(StringUtils.isNotBlank(request.getName()), "name", request.getName())
                .gt("age", 18)
                .between("birthday", new Date(), new Date())
                .like("nickName", "%og%")
                .build();
        Sort sort = Sorts.builder()
                .desc(StringUtils.isNotBlank(request.getName()), "name")
                .asc("birthday")
                .build();
        return personRepository.findAll(specification, new PageRequest(0, 15, sort));
    }
至此,用Specification查询就应该够用了,再配合JpaRepository (SimpleJpaRepository)提供的方法 和@Query注解方法,和criteria api查询,这四种JPA查询就可以解决大多数应用问题了。