Clone MySQL database

Question

I have database on a server with 120 tables.

I want to clone the whole database with a new db name and the copied data.

Is there an efficient way to do this?

Answer 1

$ mysqldump yourFirstDatabase -u user -ppassword > yourDatabase.sql
$ mysql yourSecondDatabase -u user -ppassword < yourDatabase.sql

Answer 2

mysqldump -u <user> --password=<password> <DATABASE_NAME> | mysql -u <user> --password=<password> -h <hostname> <DATABASE_NAME_NEW>

Answer 3

Like accepted answer but without .sql files:

mysqldump sourcedb -u <USERNAME> -p<PASS> | mysql destdb -u <USERNAME> -p<PASS>

Answer 4

In case you use phpMyAdmin

1. Select the database you wish to copy (by clicking on the database from the phpMyAdmin home screen).
2. Once inside the database, select the Operations tab.
3. Scroll down to the section where it says "Copy database to:"
4. Type in the name of the new database.
5. Select "structure and data" to copy everything. Alternately, you can select "Structure only" if you want the columns but not the data.
6. Check the box "CREATE DATABASE before copying" to create a new database.
7. Check the box "Add AUTO_INCREMENT value."
8. Click on the Go button to proceed.

Answer 5

There is mysqldbcopy tool from the MySQL Utilities package. http://dev.mysql.com/doc/mysql-utilities/1.3/en/mysqldbcopy.html

Answer 6

$newdb = (date('Y')-1);
$mysqli->query("DROP DATABASE `".$newdb."`;");
$mysqli->query("CREATE DATABASE `".$newdb."`;");

$query = "
SELECT
TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_SCHEMA LIKE 'rds'
";
$result = $mysqli->query($query)->fetch_all(MYSQLI_ASSOC);
foreach($result as $val) {
    echo $val['TABLE_NAME'].PHP_EOL;
    $mysqli->query("CREATE TABLE `".$newdb."`.`".$val['TABLE_NAME']."` LIKE rds.`".$val['TABLE_NAME']."`");
    $mysqli->query("INSERT `".$newdb."`.`".$val['TABLE_NAME']."` SELECT * FROM rds.`".$val['TABLE_NAME']."`");
}