问题
If I have a text file with the following conent
red apple
green apple
green apple
orange
orange
orange
Is there a Linux command or script that I can use to get the following result?
1 red apple
2 green apple
3 orange
回答1:
Send it through sort (to put adjacent items together) then uniq -c to give counts, i.e.:
sort filename | uniq -c
and to get that list in sorted order (by frequency) you can
sort filename | uniq -c | sort -nr
回答2:
Almost the same as borribles' but if you add the d param to uniq it only shows duplicates.
sort filename | uniq -cd | sort -nr
回答3:
uniq -c file
and in case the file is not sorted already:
sort file | uniq -c
回答4:
Try this
cat myfile.txt| sort| uniq
回答5:
cat <filename> | sort | uniq -c
回答6:
Can you live with an alphabetical, ordered list:
echo "red apple
> green apple
> green apple
> orange
> orange
> orange
> " | sort -u
?
green apple
orange
red apple
or
sort -u FILE
-u stands for unique, and uniqueness is only reached via sorting.
A solution which preserves the order:
echo "red apple
green apple
green apple
orange
orange
orange
" | { old=""; while read line ; do if [[ $line != $old ]]; then echo $line; old=$line; fi ; done }
red apple
green apple
orange
and, with a file
cat file | {
old=""
while read line
do
if [[ $line != $old ]]
then
echo $line
old=$line
fi
done }
The last two only remove duplicates, which follow immediately - which fits to your example.
echo "red apple
green apple
lila banana
green apple
" ...
Will print two apples, split by a banana.
回答7:
To just get a count:
$> egrep -o '\w+' fruits.txt | sort | uniq -c
3 apple
2 green
1 oragen
2 orange
1 red
To get a sorted count:
$> egrep -o '\w+' fruits.txt | sort | uniq -c | sort -nk1
1 oragen
1 red
2 green
2 orange
3 apple
EDIT
Aha, this was NOT along word boundaries, my bad. Here's the command to use for full lines:
$> cat fruits.txt | sort | uniq -c | sort -nk1
1 oragen
1 red apple
2 green apple
2 orange
来源:https://stackoverflow.com/questions/6447473/linux-command-or-script-counting-duplicated-lines-in-a-text-file