Node.js check if path is file or directory

浪尽此生 提交于 2019-11-28 15:06:09
Jason Sperske

fs.lstatSync(path_string).isDirectory() should tell you. From the docs:

Objects returned from fs.stat() and fs.lstat() are of this type.

stats.isFile()
stats.isDirectory()
stats.isBlockDevice()
stats.isCharacterDevice()
stats.isSymbolicLink() (only valid with fs.lstat())
stats.isFIFO()
stats.isSocket()

NOTE: The above solution will throw an Error if; for ex, the file or directory doesn't exist. If you want a truthy or falsy try fs.existsSync(dirPath) && fs.lstatSync(dirPath).isDirectory(); as mentioned by Joseph in the comments below.

Update: Node.Js >= 10

We can use the new fs.promises API

Experimental This feature is still under active development and subject to non-backwards compatible changes, or even removal, in any future version. Use of the feature is not recommended in production environments. Experimental features are not subject to the Node.js Semantic Versioning model.

const fs = require('fs').promises;

(async() => {

        try {
            const stat = await fs.lstat('test.txt');
            console.log(stat.isFile());
        } catch(err) {
            console.error(err);
        }
})();

Any Node.Js version

Here's how you would detect if a path is a file or a directory asynchronously, which is the recommended approach in node. using fs.lstat

const fs = require("fs");

let path = "/path/to/something";

fs.lstat(path, (err, stats) => {

    if(err)
        return console.log(err); //Handle error

    console.log(`Is file: ${stats.isFile()}`);
    console.log(`Is directory: ${stats.isDirectory()}`);
    console.log(`Is symbolic link: ${stats.isSymbolicLink()}`);
    console.log(`Is FIFO: ${stats.isFIFO()}`);
    console.log(`Is socket: ${stats.isSocket()}`);
    console.log(`Is character device: ${stats.isCharacterDevice()}`);
    console.log(`Is block device: ${stats.isBlockDevice()}`);
});

Note when using the synchronous API:

When using the synchronous form any exceptions are immediately thrown. You can use try/catch to handle exceptions or allow them to bubble up.

try{
     fs.lstatSync("/some/path").isDirectory()
}catch(e){
   // Handle error
   if(e.code == 'ENOENT'){
     //no such file or directory
     //do something
   }else {
     //do something else
   }
}

Seriously, question exists five years and no nice facade?

function is_dir(path) {
    try {
        var stat = fs.lstatSync(path);
        return stat.isDirectory();
    } catch (e) {
        // lstatSync throws an error if path doesn't exist
        return false;
    }
}

Depending on your needs, you can probably rely on node's path module.

You may not be able to hit the filesystem (e.g. the file hasn't been created yet) and tbh you probably want to avoid hitting the filesystem unless you really need the extra validation. If you can make the assumption that what you are checking for follows .<extname> format, just look at the name.

Obviously if you are looking for a file without an extname you will need to hit the filesystem to be sure. But keep it simple until you need more complicated.

const path = require('path');

function isFile(pathItem) {
  return !!path.extname(pathItem);
}

The answers above check if a filesystem contains a path that is a file or directory. But it doesn't identify if a given path alone is a file or directory.

The answer is to identify directory-based paths using "/." like --> "/c/dos/run/." <-- trailing period.

Like a path of a directory or file that has not been written yet. Or a path from a different computer. Or a path where both a file and directory of the same name exists.

// /tmp/
// |- dozen.path
// |- dozen.path/.
//    |- eggs.txt
//
// "/tmp/dozen.path" !== "/tmp/dozen.path/"
//
// Very few fs allow this. But still. Don't trust the filesystem alone!

// Converts the non-standard "path-ends-in-slash" to the standard "path-is-identified-by current "." or previous ".." directory symbol.
function tryGetPath(pathItem) {
    const isPosix = pathItem.includes("/");
    if ((isPosix && pathItem.endsWith("/")) ||
        (!isPosix && pathItem.endsWith("\\"))) {
        pathItem = pathItem + ".";
    }
    return pathItem;
}
// If a path ends with a current directory identifier, it is a path! /c/dos/run/. and c:\dos\run\.
function isDirectory(pathItem) {
    const isPosix = pathItem.includes("/");
    if (pathItem === "." || pathItem ==- "..") {
        pathItem = (isPosix ? "./" : ".\\") + pathItem;
    }
    return (isPosix ? pathItem.endsWith("/.") || pathItem.endsWith("/..") : pathItem.endsWith("\\.") || pathItem.endsWith("\\.."));
} 
// If a path is not a directory, and it isn't empty, it must be a file
function isFile(pathItem) {
    if (pathItem === "") {
        return false;
    }
    return !isDirectory(pathItem);
}

Node version: v11.10.0 - Feb 2019

Last thought: Why even hit the filesystem?

Here's a standalone function that I use in some of my programs. Nobody is making use of promisify and await/async feature in this post so I thought I would share.

const isDirectory = async path => {
  try {
    return (await require('util').promisify(require('fs').lstat)(path)).isDirectory()
  } catch (e) {
    return false // or custom the error
  }
}

Note : I don't use require('fs').promises; because it has been experimental for one year now, rather not rely on it.

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!