Why can't assign I <? extends Type> to <Type>?

只谈情不闲聊 提交于 2019-11-28 13:36:34

Covariance vs contravariance vs invariance

  • Class<? extends URLClassLoader> is invariant.

As a result,

Class<? extends URLClassLoader> is not a subtype of Class<URLClassLoader>


In Java a variable can hold a reference of an instance of same type or subtype.

Hence,

Class<URLClassLoader> uclc = ucl.getClass();

is invalid.

On the other hand,

Class<? extends URLClassLoader> uclc = ucl.getClass();

would be valid.

Why can't assign I <? extends Type> to <Type>?

Because actually <? extends Type> is a supertype of <Type>! Let's follow the specification.

4.10.2 Subtyping among Class and Interface Types:

Given a generic type declaration C<F1,...,Fn>, the direct supertypes of the parameterized type C<T1,...,Tn> are all of the following:

  • C<S1,...,Sn>, where Si contains Ti.

4.5.1. Type Arguments of Parameterized Types:

A type argument T1 is said to contain another type argument T2, written T2 <= T1, if the set of types denoted by T2 is provably a subset of the set of types denoted by T1 under the reflexive and transitive closure of the following rules:

  • T <= ? extends T

We therefore know that since ? extends URLClassLoader contains URLClassLoader, Class<? extends URLClassLoader> is a supertype of Class<URLClassLoader>.

Because a narrowing reference conversion is not permitted within an assignment context, a compilation error occurs.

Also note that this means the reverse assignment is permitted:

Class<URLClassLoader> concrete = URLClassLoader.class;
Class<? extends URLClassLoader> wildcard = concrete;
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!