A - How far away ?
HDU - 2586LCA倍增

#include<cstdio>
#include<iostream>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<stack>
#include<cstdlib>
#include<queue>
#include<set>
#include<string.h>
#include<vector>
#include<deque>
#include<map>
using namespace std;
#define INF 0x3f3f3f3f3f3f3f3f
#define inf 0x3f3f3f3f
#define eps 1e-4
#define bug printf("*********\n")
#define debug(x) cout<<#x"=["<<x<<"]" <<endl
typedef long long LL;
typedef long long ll;
const int maxn = 4e4 + 5;
const int mod = 998244353;
int cnt,DEG = 30;
int vis[maxn],head[maxn],dep[maxn],fa[maxn][30],dis[maxn];
//dep深度数组 fa[i][j]表示结点 i 的第2 ^ j个祖先
//dis[i] root到任意的一个i结点的距离
struct EDGE {
int next,to,v;
}edge[maxn * 2];
void addedge(int x,int y,int z) {
edge[++cnt].to = y;
edge[cnt].v = z;
edge[cnt].next = head[x];
head[x] = cnt;
}
void init() {
cnt = 0;
memset(vis,0,sizeof vis);
memset(head,-1,sizeof head);
memset(dep,0,sizeof dep);
memset(dis,0,sizeof dis);
memset(fa,0,sizeof fa);
}
void bfs(int root) {
queue<int>que;
dep[root] = 0; //根节点的深度为0
fa[root][0] = root;
que.push(root);
while(!que.empty()) {
int tmp = que.front(); que.pop();
for(int i = 1; i < DEG; i++)
fa[tmp][i] = fa[fa[tmp][i - 1]][i - 1]; //tmp这个点的2 ^ i的祖先就是 tmp的 2 ^ (i - 1)的祖先这个点的 2 ^ (i - 1)的祖先
for(int i = head[tmp]; i != -1; i = edge[i].next) {
int v = edge[i].to;
if(v == fa[tmp][0]) continue;
dep[v] = dep[tmp] + 1;
dis[v] = dis[tmp] + edge[i].v; //dis距离数组的更新
fa[v][0] = tmp;
que.push(v);
}
}
}
int LCA(int u,int v) {
if(dep[u] > dep[v]) swap(u,v); //使得v的深度比较大
int hu = dep[u],hv = dep[v],tu = u,tv = v;
for(int det = hv - hu, i = 0; det; det >>= 1, i++)
if(det & 1)
tv = fa[tv][i];
if(tu == tv)
return tu;
for(int i = DEG - 1; i >= 0; i--) {
if(fa[tu][i] == fa[tv][i]) continue;
tu = fa[tu][i];
tv = fa[tu][i];
}
return fa[tu][0];
}
int main()
{
int t;
scanf("%d",&t);
while (t -- ) {
init();
int n, m;
scanf("%d %d",&n,&m);
for(int i = 1; i < n; i++) {
int u,v,k;
scanf("%d %d %d",&u,&v,&k);
vis[v] = 1;
addedge(u,v,k);
addedge(v,u,k);
}
int root;
for(int i = 1; i <= n; i++ ) {
if(vis[i] == 0) {
root = i;
break;
}
}
bfs(root);
for(int i = 1; i <= m; i++) {
int a,b;
scanf("%d %d",&a,&b);
int ans = dis[a] + dis[b] - 2 * dis[LCA(a,b)];
printf("%d\n",ans);
}
}
}
