RxSwift merge different kind of Observables

99封情书 提交于 2019-11-28 10:54:48

To merge them, they need to have the same type for their Element.

So, one option is to throw away their type information and cast to AnyObject. Now they can be merged:

let stringSubject = PublishSubject<String>()
let stringObservable = stringSubject.asObservable().map { $0 as AnyObject }

let intSubject = PublishSubject<Int>()
let intObservable = intSubject.asObservable().map { $0 as AnyObject }

Observable.of(stringObservable, intObservable).merge()
    .subscribeNext { print($0) }
    .addDisposableTo(disposeBag)

stringSubject.onNext("a")
stringSubject.onNext("b")
intSubject.onNext(1)
intSubject.onNext(2)
stringSubject.onNext("c")

Output:

a
b
1
2
c

Another option would be to wrap then in an enum:

enum Container {
    case S(String)
    case I(Int)
}

let stringSubject = PublishSubject<String>()
let stringObservable = stringSubject.asObservable().map { Container.S($0) }

let intSubject = PublishSubject<Int>()
let intObservable = intSubject.asObservable().map { Container.I($0) }

Observable.of(stringObservable, intObservable).merge()
    .subscribeNext { e in
        switch e {
        case .S(let str):
            print("next element is a STRING: \(str)")
        case .I(let int):
            print("next element is an INT: \(int)")
        }
    }
    .addDisposableTo(disposeBag)

stringSubject.onNext("a")
stringSubject.onNext("b")
intSubject.onNext(1)
intSubject.onNext(2)
stringSubject.onNext("c")

Output:

next element is a STRING: a
next element is a STRING: b
next element is an INT: 1
next element is an INT: 2
next element is a STRING: c

As for the other operators that can combine Observables of varying types (like zip and combineLatest), none work quite like merge. However, check those out. They might be better suited to your requirements.

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