Setting query string using Fetch GET request

笑着哭i 提交于 2019-11-26 06:27:49

问题


I\'m trying to use the new Fetch API: https://developer.mozilla.org/en/docs/Web/API/Fetch_API

I am making a GET request like this:

var request = new Request({
  url: \'http://myapi.com/orders\',
  method: \'GET\'
});
fetch(request);

However, I\'m unsure how to add a query string to the GET request. Ideally I want to be able to make a GET request to a URL like:

\'http://myapi.com/orders?order_id=1\'

In jQuery I could do this by passing {order_id: 1} as the data parameter of $.ajax(). Is there an equivalent way to do that with the new Fetch API?


回答1:


Update March 2017:

URL.searchParams support has officially landed in Chrome 51, but other browsers still require a polyfill.


The official way to work with query parameters is just to add them onto the URL. From the spec, this is an example:

var url = new URL("https://geo.example.org/api"),
    params = {lat:35.696233, long:139.570431}
Object.keys(params).forEach(key => url.searchParams.append(key, params[key]))
fetch(url).then(/* … */)

However, I'm not sure Chrome supports the searchParams property of a URL (at the time of writing) so you might want to either use a third party library or roll-your-own solution.

Update April 2018:

With the use of URLSearchParams constructor you could assign a 2D array or a object and just assign that to the url.search instead of looping over all keys and append them

var url = new URL('https://sl.se')

var params = {lat:35.696233, long:139.570431} // or:
var params = [['lat', '35.696233'], ['long', '139.570431']]

url.search = new URLSearchParams(params).toString();

fetch(url)

Sidenote: URLSearchParams is also available in NodeJS

const { URL, URLSearchParams } = require('url');



回答2:


As already answered, this is per spec not possible with the fetch-API, yet. But I have to note:

If you are on node, there's the querystring package. It can stringify/parse objects/querystrings:

var querystring = require('querystring')
var data = { key: 'value' }
querystring.stringify(data) // => 'key=value'

...then just append it to the url to request.


However, the problem with the above is, that you always have to prepend a question mark (?). So, another way is to use the parse method from nodes url package and do it as follows:

var url = require('url')
var data = { key: 'value' }
url.format({ query: data }) // => '?key=value'

See query at https://nodejs.org/api/url.html#url_url_format_urlobj

This is possible, as it does internally just this:

search = obj.search || (
    obj.query && ('?' + (
        typeof(obj.query) === 'object' ?
        querystring.stringify(obj.query) :
        String(obj.query)
    ))
) || ''



回答3:


let params = {
  "param1": "value1",
  "param2": "value2"
}

let query = Object.keys(params)
             .map(k => encodeURIComponent(k) + '=' + encodeURIComponent(params[k]))
             .join('&');

let url = 'https:example.com//xyz.com/search?' + query

fetch(url)
  .then(data => data.text())
  .then((text) => {
    console.log('request succeeded with JSON response', text)
  }).catch(function (error) {
    console.log('request failed', error)
  })



回答4:


You can use #stringify from query string

import { stringify } from 'query-string';

fetch(`https://example.org?${stringify(params)}`)



回答5:


encodeQueryString — encode an object as querystring parameters

/**
 * Encode an object as url query string parameters
 * - includes the leading "?" prefix
 * - example input — {key: "value", alpha: "beta"}
 * - example output — output "?key=value&alpha=beta"
 * - returns empty string when given an empty object
 */
function encodeQueryString(params) {
    const keys = Object.keys(params)
    return keys.length
        ? "?" + keys
            .map(key => encodeURIComponent(key)
                + "=" + encodeURIComponent(params[key]))
            .join("&")
        : ""
}

encodeQueryString({key: "value", alpha: "beta"})
 //> "?key=value&alpha=beta"



回答6:


Maybe this is better:

const withQuery = require('with-query');

fetch(withQuery('https://api.github.com/search/repositories', {
  q: 'query',
  sort: 'stars',
  order: 'asc',
}))
.then(res => res.json())
.then((json) => {
  console.info(json);
})
.catch((err) => {
  console.error(err);
});



回答7:


I know this is stating the absolute obvious, but I feel it's worth adding this as an answer as it's the simplest of all:

var orderId = 1;
var request = new Request({
  url: 'http://myapi.com/orders?order_id=' + 1,
  method: 'GET'
});
fetch(request);



回答8:


Template literals are also a valid option here, and provide a few benefits.

You can include raw strings, numbers, boolean values, etc:

    let request = new Request(`https://example.com/?name=${'Patrick'}&number=${1}`);

You can include variables:

    let request = new Request(`https://example.com/?name=${nameParam}`);

You can include logic and functions:

    let request = new Request(`https://example.com/?name=${nameParam !== undefined ? nameParam : getDefaultName() }`);

As far as structuring the data of a larger query string, I like using an array concatenated to a string. I find it easier to understand than some of the other methods:

let queryString = [
  `param1=${getParam(1)}`,
  `param2=${getParam(2)}`,
  `param3=${getParam(3)}`,
].join('&');

let request = new Request(`https://example.com/?${queryString}`, {
  method: 'GET'
});



回答9:


A concise ES6 approach:

fetch('https://example.com?' + new URLSearchParams({
    foo: 'value',
    bar: 2,
}))

URLSearchParam's toString() function will convert the query args into a string that can be appended onto the URL. In this example, toString() is called implicitly when it gets concatenated with the URL.

IE does not support this feature, but there are polyfills available.



来源:https://stackoverflow.com/questions/35038857/setting-query-string-using-fetch-get-request

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