I would like to subtract 4 hours from a date. I read the date string into an NSDate object use the following code:
NSDateFormatter * dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZ"];
NSDate * mydate = [dateFormatter dateFromString:[dict objectForKey:@"published"]];
What do I do next?
NSDate *newDate = [theDate dateByAddingTimeInterval:-3600*4];
NSDate *newDate = [[[NSDate alloc] initWithTimeInterval:-3600*4
sinceDate:theDate]] autorelease];
NSCalendar is the general API for changing dates based on human time units. For this, you can use NSCalendar's -dateByAddingComponents:toDate:options:
with a negative number of hours.
Since iOS 8 there is the more convenient dateByAddingUnit
:
Swift 2.x
//subtract 3 hours
let calendar = NSCalendar.autoupdatingCurrentCalendar()
newDate = calendar.dateByAddingUnit(.Hour, value: -3, toDate: originalDate, options: [])
//in Swift 3
//subtract 3 hours
let calendar = NSCalendar.autoupdatingCurrent
newDate = calendar.date(byAdding:.hour, value: -3, to: originalDate)
In Swift 4 :
var baseDate = ... // something
let dateMinus4Hours = Calendar.current.date(byAdding: .hour, value: -4, to: baseDate)
don't go with 24*3600
and stuff, that's asking for trouble.
dateFromString function returns NSDate, not NSString. you should change,
NSDate * theDate = [dateFormatter dateFromString:datetemp];
Here a function which might be useful as it returns the date -4 h considering that this may also change the date and the month and eventually the year. the .searchBackward option is the important part :)
public static func correctSecondComponent(date: Date, calendar: Calendar = Calendar(identifier: Calendar.Identifier.gregorian))->Date {
let hour = calendar.component(.hour, from: date)
let e = (calendar as NSCalendar).date(byAdding: NSCalendar.Unit.hour, value: -4, to: date, options:.searchBackwards)!
return e
}
来源:https://stackoverflow.com/questions/1160977/how-does-one-subtract-hours-from-an-nsdate